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How much more light does the sun give off than an object with the least apparent magnitude that can be viewed by the naked eye
Sun's apparent visual magnitude: - 26.7Full moon's apparent visual magnitude: - 12.6Difference: The sun is 14.1 magnitudes brighter than the full moon. (Brightness ratio of 50,120)
yes but we should have a sharped eye a common person people cant see this
The apparent magnitude of the Sun is -26.73. (Yes negative)The absolute magnitude of the Sun is 4.83See related question for the difference between absolute and apparent magnitude.For comparison at maximum brightness.Full Moon -12.6Venus -3.8Mars - 3Sirius -1.47Ganymede 4.6Object visible with the naked eye 6.5
2nd magnitude is brighter than 3rd. 6th magnitude is the dimmest that can be seen with the naked eye; many more can be seen in binoculars, telescopes etc.
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No, at brightest, it will shine at magnitude 11.2 or five levels below what the naked eye can see.
Magnitude. First magnitude descibes many bright stars, and a span of five magnitudes represents a difference of a hundred times in the star's brightness. The dimmest stars seen by a perfect human eye in perfect conditions is 6th magnitude.
No. Its apparent magnitude (i.e., brightness) is about 8; with the naked eye, we can see objects up to approximately magnitude 6.
How much more light does the sun give off than an object with the least apparent magnitude that can be viewed by the naked eye
No. Its apparent magnitude (i.e., brightness) is about 8; with the naked eye, we can see objects up to approximately magnitude 6.
The sun's apparent visual magnitude is listed as -26.74.When you say the "greatest apparent magnitude", I take that to mean thedimmest object that the naked eye can detect in good seeing conditions.It varies among individuals and their eyes, but the figure of 6th magnitudeis usually considered the benchmark limit for the general population.So that's a span of 32.74 magnitudes, or a brightness ratio of 1.247 x 1013 .Do you hear that ? That's saying that the sun is 12,473,835,000,000 times as brightas the dimmest thing that your eye can see in the night sky. Now that's bright!(Engineering alert: That's almost exactly 131 dB ... the difference between1 nanowatt and 12,474 watts.)
Yes, but only if the conditions are right. 51 Pegasi has an apparent magnitude [See Link] of 5.49. The faintest object the naked eye can see, has an apparent magnitude of 6.5 (in perfect conditions). Even with binoculars, the faintest object is 9.5. The larger the apparent magnitude, the dimmer the object is. Our Sun has an apparent magnitude of -26.73 (yes minus)
Sun's apparent visual magnitude: - 26.7Full moon's apparent visual magnitude: - 12.6Difference: The sun is 14.1 magnitudes brighter than the full moon. (Brightness ratio of 50,120)
I think you are referring to what astronomers call magnitude, which is defined in several different ways. Apparent magnitude is how bright a star looks compared to others. The dimmest stars we can see with the naked eye in good conditions are magnitude 6, and the brightest ones are about 1. Really bright objects like some of the planets have negative magnitude. Absolute magnitude is a way to compare how bright stars really are, because the apparent magnitude is affected by their distance from us. It's the magnitude the star would have if it were exactly ten parsecs away. Bolometric magnitude is more complex, but is an attempt to quantify the star's luminosity over all wavelengths, not just those we can see.