Since the earth is not perfectly round, distances vary slightly. From the poles to the center its about 3950 miles. From the equator to the center its about 3960 miles The correct answer is the earth has an equitoral circumference of ~ 24,900 mi and diameter of ~ 7,926mi. With these facts we devise the surface to core distance to be ~3963mi at the equator and 3950mi from the poles.
The center point of the Earth lies at an average depth of 3977 miles (6400 km) from the surface.
700 kilometers / 700,000 meters
The average distance from Earth's surface at the equator its center is about 6378 km. The distance from near the north and south poles to the center is somewhat less.
-- If your mass is 'm', then your mass is 'm', regardless of whether you're on the earth,2 earth radii out in space, or on the moon. Mass doesn't change.-- On the surface, your distance from the center of the earth is 1 earth radius. Weight isinversely proportional to the square of the distance from the center of the earth, so at adistance of 3 earth radii from the center, your weight is 1/32 = 1/9th of your weight on thesurface. If your mass is 'm' then your weight on the surface is mg = 9.8m newtons, and at3 earth radii from the center it's 1.089m newtons (rounded).
It is the average distance between the centres of the two objects.
The average height of the troposphere is 17km above the surface of the Earth.The average radius of the earth, that is the distance from its center, is 6378.1km. The two combined give a distance of 6395.1km, which would be the average distance from the top of the troposphere to the center of the Earth.
I'm thinking center to equator
The average distance from Earth's surface at the equator its center is about 6378 km. The distance from near the north and south poles to the center is somewhat less.
7,000 km
I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.
That's the Earth's radius. It's about 6378 kilometers at the equator. That's 3963 miles.
That's the Earth's radius. It's about 6378 kilometers at the equator. That's 3963 miles.
diameter
-- Your weight depends on the mass of the other mass to which you are gravitationallyattracted, and also on your distance from its center.-- The mass of the moon is much less than the mass of the Earth.-- The moon's surface is much closer to its center than the Earth's surface is to its center.
That's the Earth's radius. It's about 6378 kilometers at the equator. That's 3963 miles.
-- If your mass is 'm', then your mass is 'm', regardless of whether you're on the earth,2 earth radii out in space, or on the moon. Mass doesn't change.-- On the surface, your distance from the center of the earth is 1 earth radius. Weight isinversely proportional to the square of the distance from the center of the earth, so at adistance of 3 earth radii from the center, your weight is 1/32 = 1/9th of your weight on thesurface. If your mass is 'm' then your weight on the surface is mg = 9.8m newtons, and at3 earth radii from the center it's 1.089m newtons (rounded).
The earth is an regular surface in average with a great number of small irregularities (small with respect to the global earth surface). The geometrical center of earth is obtained by approximating the earth surface with the best fitting rotational ellipsoid, with a circular section corresponding to the equator and a minor axis joining the geographical poles. The so called "sea level" is defined as the average distance from the geometrical center of earth of all the points on the sea surface. The altitude of a single earth point is the difference between the distance from the earth center of that point and the conventional sea level.
Assuming you mean from the center of the Earth: 1/22 = 1/4, that is, 1/4 the gravity at the Earth's surface. If you mean two Earth radii from the surface, then the distance from the Earth's center would be 3 times as much, and the force would be 1/9, compared to the Earth's surface. _______________________________ The force of gravity changes with the reciprocal of the square of the distance. So if the distance is increased by a factor of 2, the force will DECREASE by a factor of two squared, or 4. So, double the distance = one-quarter the force.
The distance from surface to surface through the center of a planet would be that planet's "diameter".