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I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.

I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.

I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.

I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.

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What is the distance between the surface at the center of a reflective surface and the focal point?

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What is the spherical radius of 1 foot?

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What would be its relative strength at the new surface if Earth's radius shrank to 0.65 its size?

If you are asking about gravity, its strength depends on the mass and the distance from the centre, so the force varies as M/r^2. If you assume the mass stays the same, gravity at the surface would be 1/(0.65^2) times stronger for that reduction in radius, so a little more than twice as strong.


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What is the radius of a sphere?

A radius of a sphere is the distance from its centre to its surface. It is also half of the diameter. If you know the circumference of a circle, you can calculate its radius. Circumference divided by Pi divided by 2 = radius.


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The radius of the Earth is 6378.1 kilometers or about 3961.3 miles


What is the difference between Radius of curvature and centre of curvature?

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The word you're looking for is radius.


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