Since you can't take the square root of a negative number, the expression under the square root must be equal to, or greater than, zero. Just solve this inequality, with the expression under the square root.
If I understand correctly, the expression under the root is 9x2-4. For the inequality, get the critical points through an equation first: 9x2-4 = 0; 9x2 = 4; x2 = 4/9; x = plus-or-minus 2/3. Analyzing any points to the left of -2/3, between -2/3 and 2/3, and to the right of 2/3, you quickly see that the inequality is fulfilled for any number that is either <= -2/3, or >= 2/3.
Domain is greater than or equal to zero. same with range
No, id does not.
The square root of 1753 equals 2,315.0324(rounded).
That would be a number to the 6th power, like 64.
12
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
Domain is greater than or equal to zero. same with range
The square root of 1753 equals 2,315.0324(rounded).
No, id does not.
The square root of 2 raised to the fifth power equals 5.65685424949
That would be a number to the 6th power, like 64.
12
y=(√1)-x2 The domain is the set of numbers that "x" can be. In this equation "x" can be any real number. The domain for this problem would be (-inf,inf) *Inf= Infinity*
rearrange the following: A^(1/n)= the nth root of A. eg A to the power 1/2 equals the square root of A. A to the power 1/3 equals the cube root of A. etc.
Square root of 6.25 equals ± 2.5
square root of x = 3 Since the square root of a number is basically that number to the power of 1/2, if you square both sides it will cancel out the square root.(x1/2)2 = 32x = 32x = 9Since 3 squared is 9, x equals 9.
The square root of 12 equals the square root of 4 times 3. The square root of 4 is 2. The square root of 12 equals 2 times the square root of 3.