Math and Arithmetic
Algebra
Calculus

# What is the domain of x squared plus y squared equals thirty six?

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The graph is a circle with a radius of 6, centered at the origin

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## Related Questions Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range. The answer depends on the domain for x. For example, if the domain is x = 7, then the range is 55. If the domain is all Real numbers, then the range is y &gt;= 6.   you use A squared plus B squared equals C squared 2 squared plus 2 squared equals 16 because 2 squared is 4 times 4 equals 16. Math: 4x4=16 so your answer is 16 :)! 2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.     Well pythagorus theoreum is a squared plus b squared equals c squared and circumference equals pie x diameter and area equals pie x radius squared a2+b2=c2 a squared plus b squared equals c squared Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.    'A' squared plus 'B' squared equals 'C' squared. If 'A' and 'B' are the legs of the right angle comprising the sides of the box, 30 inches squared (900) plus 30 inches squared (900) equals 1800. The square root of 1800 is 42.426408711929. A squared plus B squared equals C squared, where C is the hypotenuse of a right triangle and A and B are the other two sides is true and is one way of expressing the Pythagorean Theorem.   Pythagoras' theorem in finding the lengths of the sides of a right angled triangle. what is the domain of g(x) equals square root of x plus 1? &radic;(x+1) &ge; 0 x+1&ge;0 x&ge;-1 Domain: [-1,&infin;) Until an "equals" sign shows up somewhere in the expression, there's nothing to prove. It depends on the domain but, if the domain is the real numbers, so is the range.

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