The answer is CH3COOK+H2O.
A double replacement reaction means that you would need to figure out what is being swapped. Think of it like this:
AB+CD --> AC+BD
KOH is a base, which separates into K+ and -OH in solution; likewise CH3COOH (an acid) separates into CH3COO- and H+. The double replacement product couples K+ and CH3COO- together, and coupling H- with -OH to form H2O (water).
Good luck.
hf + koh -> h2o + kf
Acetic acid is an organic acid an d it reacts with potassium hydroxide to form salt and water Its neuatralisation reaction CH3CooH + KOH -------> CH3COOK + H2O
CH3COOH + KOH = CH3COOK + H2O
This problem is a Double Reactant. "K+ H20 ----> KOH + H2" would equal "2K + 2H20 ---> 2KOH + H2"
HNO3 + KOH ---> KNO3 + H2O
hf + koh -> h2o + kf
Acetic acid is an organic acid an d it reacts with potassium hydroxide to form salt and water Its neuatralisation reaction CH3CooH + KOH -------> CH3COOK + H2O
CH3COOH + KOH = CH3COOK + H2O
This problem is a Double Reactant. "K+ H20 ----> KOH + H2" would equal "2K + 2H20 ---> 2KOH + H2"
HNO3 + KOH ---> KNO3 + H2O
KOH + HCl ---> KCl + H2O
Acids-HCl,HNO3,SO3,CH3COOH,H2SO4 bases-NaOH,Ba(OH)2,NH3,NH4OH,KOH
The chemical equation is:H3PO4 + 3 KOH = K3PO4 + 3 H2O
Balanced :2 K + 2 H2O ----> 2 KOH + H2
ZnO+ KOH→K2O+Zn(OH)2
neutralization reaction
yes