The answer is CH3COOK+H2O.
A double replacement reaction means that you would need to figure out what is being swapped. Think of it like this:
AB+CD --> AC+BD
KOH is a base, which separates into K+ and -OH in solution; likewise CH3COOH (an acid) separates into CH3COO- and H+. The double replacement product couples K+ and CH3COO- together, and coupling H- with -OH to form H2O (water).
Good luck.
CH3COOH + KOH = CH3COOK + H2O
C_2_H_4_O_2_ (aq) + OH^-^ (aq) --> C_2_H_3_O_2_^-^ (aq) + H_2_O (l)
The preparation equation depends on the route by which this compound is prepared. A simple route is neutralization of acetic acid with potassium hydroxide: KOH + CH3COOH --> H2O + K+CH3COO-
CH3COOH + OH ---> CH3COO + H2O CH3COOH stays as a molecule because it is a weak acid
The reaction between KOH and CO2 to produce K2CO3 and H2O is a double displacement reaction, also known as a neutralization reaction. In this reaction, the ions in KOH and CO2 switch partners to form new compounds K2CO3 and H2O.
CH3COOH + KOH = CH3COOK + H2O
C_2_H_4_O_2_ (aq) + OH^-^ (aq) --> C_2_H_3_O_2_^-^ (aq) + H_2_O (l)
The preparation equation depends on the route by which this compound is prepared. A simple route is neutralization of acetic acid with potassium hydroxide: KOH + CH3COOH --> H2O + K+CH3COO-
CH3COOH + OH ---> CH3COO + H2O CH3COOH stays as a molecule because it is a weak acid
The reaction between KOH and CO2 to produce K2CO3 and H2O is a double displacement reaction, also known as a neutralization reaction. In this reaction, the ions in KOH and CO2 switch partners to form new compounds K2CO3 and H2O.
KOH(aq)+HC2H3O2(aq)---- H2O(l)+KC2H3O2(aq)
Acetic acid (Ethanoic acid) is a weak acid, and when reacted with a strong base like Potassium hydroxide, it establishes an equilibrium: CH3COOH + KOH <=> CH3COOK + H2O The reaction mixture contains all four products in different proportions, and as such, an acid buffer is created. When an acid is added, the CH3COO- ions (those mixed with the K+ ions) 'mop up' the H+ ions from the acid. When a base is added, the H+ ions from the CH3COOH 'mop up' the OH- ions so the pH is little affected. NB. pH=-log10(H+)
Acids-HCl,HNO3,SO3,CH3COOH,H2SO4 bases-NaOH,Ba(OH)2,NH3,NH4OH,KOH
The chemical equation for the reaction between acetic acid (CH3COOH) and potassium hydroxide (KOH) is: CH3COOH + KOH -> CH3COOK + H2O. This reaction is a neutralization reaction that forms potassium acetate (CH3COOK) and water (H2O).
The given chemical reaction is a double displacement reaction, also known as a metathesis reaction. In this reaction, the cations and anions from two different compounds switch places to form new compounds: NaOH + KNO3 → NaNO3 + KOH.
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O