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The effect of low (or 'poor') power factor is that a given load requires more load current than at high power factors. So, to accommodate these higher currents, a greater volume of copper is required in the supply cables, switchgear, transformers, etc. So much greater capital costs are required if low power loads are supplied.
Power factor cannot exceed unity!
A poor power factor causes the meter to rotate more slowly than it should, so a poor power factor would reduce your bill. Electric utilities compensate for this in commercial services by billing based on power factor, or they install a meter that actually measures power factor.AnswerEnergy meters 'read' the in-phase component of load current (therefore the load's 'true power' multiplied by time) and, so, are completely unaffected by the power factor of a load. So the power factor of a residential load will have absolutely no effect whatsoever on that residence's 'energy' (not 'power') bill.Industrial and commercial consumers are billed for 'demand' (their rate of consumption of energy -i.e. the power) as well as energy supplied'. In addition, these consumers are usually penalised if the power factor of their load falls below an agreed value. So power factor does affect the overall bill (but not the energy bill) of industrial consumers.
An induction motor has a lagging power factor. Motors of more than about 2 HP are designed to have a power factor of 0.85 or higher.
If you have a poor power factor (say .8), and your local utility requires you to have .95pf or better, or be charged extra due to the poor power factor, there is no economic reason to buy more equipment to bump your power factor up to 1.0 as opposed to .95. Once you're above .95, you're just fining yourself.
Yes, they exist. Capacitors are often used to change a low power factor (such as 0.5) to a higher power factor near unity (1). In some instances, this will lower fees and costs to utilities. In homes, this is not really necessary as most devices used in homes are near unity power factor, or tend to be minor/sporadic loads (such as a washing machine).
yes it doesent
The power factor depends on the phase angle between the voltage and current on a conductor. The amplitude of the current has no effect on it.
Power factor is the cosine of angle between voltage and current that we all know. And the power factor should be unity or close to unity. Unless if we have the power factor not close to unity or far away from unity is called poor power factor. This termed as poor because it will take large amount of current for the given power. If the large amount of current is drawn from the substation or anything else then the line loss will increase. Line loss is (I^2)R loss. So the current increase line loss will also be increased. So as to avoid such losses every industry should maintain their power factor(Normally in every Industry they maintain .9 and above). Those who are not maintaining power factor will be fined.
A poor power factor is caused by inductive loads or electronic devices. These loads cause excess current to flow in the circuit reducing the efficiency. Inductive devices are considered to be a "load" for reactive power. Reactive power does not actually do any real work by is required to develop magnetic fields. Capacitors are considered to be "sources" of reactive power. So these capacitors will supply the reactive power to the inductive loads instead of the utility supplying this power. This is why capacitors are used to improve a poor or low power factor. This is just a very brief description on this topic. Power factor correction is becoming a very complex topic with more and more poor power factor loads being used every day.
VAr is reactive power, caused by either inductive or capacitive loads. The ideal power factor to have is 1, anything less than that is a loss on the network. The effect of VArs on the circuit though depends. If you have a load that is mainly inductive, then adding more inductive reactance will lower the power factor. However, if you introduce capacitive reactance this will increase the power factor, and the opposite is true if its a mainly capacitive circuit. So VArs will either increase or decrease the power factor depending on the load of the circuit. The ideal situation is to balance inductive reactance with capacitive reactance so they in effect cancel each other out and power factor is 1.
they made them feel like they had power