Want this question answered?
no due to difference of mass. see effect of gravity/velocity on time
The resolving time or dead time of a detector is the time it takes for the detector to reset.
Yes, it does. Assuming a constant force, the impulse is equal to the force multiplied by the time the force acts. (If it isn't constant, you will of course use an integral instead.)
If the distance/time graph is a straight line that makes a constant angel with the time axis, then the body's speed is constant, and is equal to the slope of the straight line (tangent of the constant angel).
Answer
The circuit that generates signal having the shape like imaginary curve is called an envelope detector. The effect of the time constant RC in envelope detector is that the output follows the input curve and the circuit performs like a demodulator.
A constant-envelope modualtion is a modualtion scheme in which the amplitude of the modualted tone remains constant with time. Main advantage of such modualtion schmes is that they relax the linearity requirements of the power amplifier (PA) and hence a less linear and more efficient PA can be used. Most modualtion schemes are not constant-envelope. For example, BPSK, QPSK, 16-QAM are not constant-envelope. Few modualtion schemes such as GFSK are constant-envelope.
The diagonal clipping in Amplitude Demodulation (using envelop detector) can be avoided if RC time-constant of the envelope detector satisfies the following condition, where W is message bandwidth and w is carrier frequency both in rad/sec: The time contant t should be always in between ( 1/w) and ( 1/W) [without including ( 1/w) and ( 1/W) ]
The passage of time has a constant erosive effect.
no due to difference of mass. see effect of gravity/velocity on time
The resolving time or dead time of a detector is the time it takes for the detector to reset.
One way to demodulate an amplitude modulated signal from its carrier is to build a peak-follower. This could be a simple RC filter with a diode at the input. The voltage across the capacitor would charge to the peak value of the carrier (envelope), and then discharge through the resistor. The time constant would be selected so that the capacitor would have no "trouble" following the envelope. Since the typical ratio of signal to carrier frequency is quite high, i.e. 20kHz signal vs 1MHz carrier, the time constant can be quite short.
Yes, it does. Assuming a constant force, the impulse is equal to the force multiplied by the time the force acts. (If it isn't constant, you will of course use an integral instead.)
An acoustic envelope is a graph that describes the pitch, volume or other such parameters of a sound over time.
Factors like decomposition and absorption of gas from the atmosphere can effect pH. Because these factors are rarely constant, pH will change over time.
The retention time represents the time it takes to an analyte to pass from the column inlet to the detector.
A resistor by itself has no time constant. For a circuit to have a time constant it must contain either capacitors or inductors.