The volume of the displaced water would be less - as you're reducing the mass of the boat.
Another viewpoint: I think there's a bit more to this question, but the basic answer remains the same. I think it's all about "Archimedes' Principle".
Let's consider the anchor as still part of the boat.
Also let's think about it before it gets partly buried in the ground underwater.
Archimedes' Principle tells us:
The "upthrust" on the boat before the anchor is lowered is equal to the weight of the whole boat. That equals the weight of water displaced.
The anchor itself doesn't float in water. It is denser than water.
When the anchor is completely submerged it displaces an amount of water equal to the anchor's volume (not the anchor's weight).
When the anchor was on the boat it displaced an amount of water equal to its weight.
So, when the anchor is lowered, the boat (including anchor) displaces a slightly smaller volume of water.
volume after anchor was in water minus volume of water without anchor in it = the volume of the anchor
In order to measure volume, one normally sees how much water it displaces. If the body floats, the water displaced will be equal to the weight of the body, not the volume. It will be necessary to force the body down so that it is totally submerged. If there is an anchor and chain below the surface, the water displaced when the body is attached and submerged will have the same volume as the body.
The amount of a liquid that is displaced by a solid = the volume of that solid. You could half fill a graduated cylinder. Drop something that sinks into the graduated cylinder to test its volume.
More water will be displaced equal to the load placed on the ship as long as the ship continues to float. This is not equal in volume, but equal in mass to that of the load.
Mass will determine how much water is displaced by something that floats. Volume will determine how much water is displaced by something that does not (that sinks).
The volume of displaced water for a metal cylinder with a volume of 50cm3 is: 13,210 US gallons of water or 11,000 UK gallons of water.
The amount of water displaced by the block is the volume of the block. so (volume of water with block in it)-(original volume of water)= volume of block
Volume
Archimedes' principle is used. Water will be displaced by the volume of what is put into it. That displaced volume can be measured giving the weight.
It's 6 kN because the loss of weight equals the weight that has been displaced, i.e. 7 - 1 = 6.
Buoyant force = Density of the water * g * Volume of displaced water For the ship to float, the buoyant force must be equal to the weight of the ship. Density of the water * g * Volume of displaced water = m * g Density of the water * Volume of displaced water = m When you multiply the density of water by the volume of displaced water, you get the mass of the ship.
Volume of liquid displaced = Volume of object submerged