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What else can I help you with?
What is work in physics?
in physics work work=force *distance the distance covered by body by any force is called work.
What is the average speed at 20 seconds?
None.Speed is the distance covered per unit of time. If no distance is covered then the speed is 0.None.Speed is the distance covered per unit of time. If no distance is covered then the speed is 0.None.Speed is the distance covered per unit of time. If no distance is covered then the speed is 0.None.Speed is the distance covered per unit of time. If no distance is covered then the speed is 0.
Is distance covered during nth second more than the distance covered in n seconds?
Distance covered in nth second means the distance covered in that particular second . It cannot be more than the distance covered in n seconds which means the distance covered in a total time of n seconds.
Is the distance covered by a body may be greater than a magnitude of the displacement?
yes,displacement is the shortest distance covered by a body,so distance covered by a body may be greater than the displacement.
How does average speed relate the distance covered and the time taken for travel?
Average speed = Distance covered/Time taken
What was the distance covered by the First Fleet?
The distance covered by the First Fleet was about 24 000 kilometres, or 15 000 miles.
Does distance effect a magnets activity?
it does effect the distance because it is far
Distance covered in one revolution of a circle with a diameter of 153 meters?
The distance covered in one revolution of this circle is 481 meters.
What is the distance covered by a bridge?
Everyone differs on that one , but I'll go with 'span' .
An athlet completes one round of a circular track of diameter 200m in 40s what will be the distance covered and the displacement at the end of 2 minutes 20s?
Distance covered - 2199m Displacement - 200m Distance covered - 2199m Displacement - 200m
Suppose work input is 25 J and the output distance is 10 m. Factoring in the effect of friction which must be true about output force?
Considering the work input and output distance, to account for the effect of friction, the output force must be greater than the input force due to the work lost to friction. This means that the output force required to move the object the specified distance against friction will be higher than what would be calculated based solely on the given work input and output distance.
How does distance change when the amount of effort force is increased while the amount of work done remains the same?
Work is the product of (force) x (distance).If, as you allege, the force increased but the work didn't change, thenthe distance must have decreased, by exactly the same factor as theincrease in the force, so that their product is not changed.
