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Assuming that the only force on the two objects is an electric force. Felectric = k Q q / r2 This is Coulomb's law. K = electrostatic constant, Q and q are the magnitudes of the point charges, and r is the distance between the point charges. As you can see, if you decrease the magnitude of the charge, the electric force decreases. In other words, the objects are less attracted to one another. aside: gravity happens to be modeled the same way.
This question is impossible to answer because the force is dependant on the strength of the electric field. This will depend on how many other charges there are and how far away. The strength of an electric field is proportional to the number of charges and the inverse square of the distance. Strength of field = C x N / D2 where C is some constant, N is the number of charges (-ve will repel +ve will attract for and electron) and D is the distance between the electron and the charges creating the field.
Well you mean Coulomb's law, the equivalent of Newton's law for electrostatic?From Wikipedia:The magnitude of the electrostatic force between two point electric charges is directly proportional to the product of the magnitudes of each of the charges and inversely proportional to the square of the total distance between the two charges.
The electric potential energy of given configuration of charges is defined as the work which must be done against the Coulomb force to rearrange charges from infinite separation to this configuration (or the work done by the Coulomb force separating the charges from this configuration to infinity). For two point-like charges Q1 and Q2 at a distance r this work, and hence electric potential energy is equal to: E_mathrm{p,e} = frac{1}{{4piepsilon_0}}{{Q_1Q_2}over{r}} ============================================ Yes, yes, undoubtedly correct. But what is an electrostatic force ? Atraction between two opposite forces
The electric potential energy of given configuration of charges is defined as the work which must be done against the Coulomb force to rearrange charges from infinite separation to this configuration (or the work done by the Coulomb force separating the charges from this configuration to infinity). For two point-like charges Q1 and Q2 at a distance r this work, and hence electric potential energy is equal to: E_mathrm{p,e} = frac{1}{{4piepsilon_0}}{{Q_1Q_2}over{r}} ============================================ Yes, yes, undoubtedly correct. But what is an electrostatic force ? Atraction between two opposite forces
Hello, some error in the words. Electric "force" not electric charge. A/s we increase the distance between the charges ./2 times then force between them will be halved.
Two point charges.
It is because when a dielectric is placed between the charges , the dielectric gets polarized and the net electric field between the two charges decreases, hence force = charge x electric field also decreases. john
acting oppisite forces make it so they cancel midway The repulsion of the like charges creates a space (Gap X) between their electric fields. At this region there would be no force felt as both charges have the same electric force magnitude; they push each other away equally, thereby making a "neutral" zone. Since there is no force the electric field would be zero.
Electric force can act at a distance, but is stronger when objects are closer. the electric force is larger the closer the two objects are The electric force varies with the distance between the charges. The closer they are, the stronger the force. The farther apart they are, the weaker the force.
Assuming that the only force on the two objects is an electric force. Felectric = k Q q / r2 This is Coulomb's law. K = electrostatic constant, Q and q are the magnitudes of the point charges, and r is the distance between the point charges. As you can see, if you decrease the magnitude of the charge, the electric force decreases. In other words, the objects are less attracted to one another. aside: gravity happens to be modeled the same way.
This question is impossible to answer because the force is dependant on the strength of the electric field. This will depend on how many other charges there are and how far away. The strength of an electric field is proportional to the number of charges and the inverse square of the distance. Strength of field = C x N / D2 where C is some constant, N is the number of charges (-ve will repel +ve will attract for and electron) and D is the distance between the electron and the charges creating the field.
Well you mean Coulomb's law, the equivalent of Newton's law for electrostatic?From Wikipedia:The magnitude of the electrostatic force between two point electric charges is directly proportional to the product of the magnitudes of each of the charges and inversely proportional to the square of the total distance between the two charges.
Coulomb's Law states that the magnitude of the electrostatic force between two point electric charges is directly proportional to the product of the magnitudes of each charge and inversely proportional to the square of the distance between the charges. A link is provided to the Wikipedia article.
The Force on a point charge from another point charge is along the Line connecting between the two charges. The direction will be towards the point charge if the two charges are different and away if they are same.Now if you collection of Charges then it is vector sum of force due to each charge.
The electric potential energy of given configuration of charges is defined as the work which must be done against the Coulomb force to rearrange charges from infinite separation to this configuration (or the work done by the Coulomb force separating the charges from this configuration to infinity). For two point-like charges Q1 and Q2 at a distance r this work, and hence electric potential energy is equal to: E_mathrm{p,e} = frac{1}{{4piepsilon_0}}{{Q_1Q_2}over{r}} ============================================ Yes, yes, undoubtedly correct. But what is an electrostatic force ? Atraction between two opposite forces
The electric potential energy of given configuration of charges is defined as the work which must be done against the Coulomb force to rearrange charges from infinite separation to this configuration (or the work done by the Coulomb force separating the charges from this configuration to infinity). For two point-like charges Q1 and Q2 at a distance r this work, and hence electric potential energy is equal to: E_mathrm{p,e} = frac{1}{{4piepsilon_0}}{{Q_1Q_2}over{r}} ============================================ Yes, yes, undoubtedly correct. But what is an electrostatic force ? Atraction between two opposite forces