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Because it takes no work to bring a test charge in from infinity along the

perpendicular bisector of the dipole (any line in the equatorial plane).

At least, that's true for any distance that's much greater than the separation

of the two charges that make up the dipole. In that case, the potential is

proportional to cos(angle between the line joining the charges and the direction

from its midpoint to the test charge). That's the angle that's 90 degrees in the

equatorial plane, and its cosine is zero.

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11y ago
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12y ago

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Q: Why is the electrostatic potential due to an electric dipole at an equatorial point zero?
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