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Answered 2007-10-02 21:08:42

The question is missing something; I must assume that the compound is 23% N by mass and 77% O by mass. Starting with NO3 as an initial guess turns up 22.6% N, 77.4% O, which agrees with the above if we round off to two significant figures. It has a molar mass of 62, precisely half the stated molecular mass. One could presume a dimer of NO3, i.e., N2O6, which is hardly a common species but does appear in the literature.

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The empirical formula for nitrogen dioxide is the same as its molecular formula - NO2. See related question below for more details on how to find empirical formulas.

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An empirical formula give information about the chemical composition of a compound. Example: tetracycline with the empirical formula C22H24N2O8 has the following composition: - carbon 59,44 % - oxygen 28,81 % - nitrogen 6,30 % - hydrogen 5,45 % If you're with plato the answer is ratios

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Yes its Molecular compound is NCL3

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it can be calculated using the formula percentage composition of N =Gram molecular mass of nitrogen in the compound/ Gram molecular mass of compound *100

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No it is ionic because when a metal (sodium) and a non-metal (nitrogen) combine it makes an ionic compound. If you combined two non-metals it would create a molecular compound.

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