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7390 m/s
Use dimensional analysis to answer this question.1 km = 1000 mMultiply 410 m by the relationship between meters and kilometers, so that meters cancel, leaving kilometers.410 m x 1 km/1000 m = 0.410 km
m stands for Mass of the object
M + ionization energy à M1+ + e- M + ionization energy à M1+ + e-
The work (energy) done on an object is Force x Distance. If there is no friction, and the object started at rest, then this will also be the kinetic energy that the object has. Then the kinetic energy, Ek = F * d, so F = Ek / d
m lmn ?,
Answer: 410 m = 1345.144 ' OR 1345 ' and 1.73 "
M. Randy McKay has written: 'The emission of atoms and molecules accompanying the fracture of single crystal magnesium oxide' -- subject(s): Thermionic emission, Electrons, Emission
Medium, emission
100 cm = 1 metre so 410 cm = 4.1 m
In excess of 50 m
B. M. Peterson has written: 'Emission Lines in Active Galaxies: New Methods and Techniques: Iau Colloquim 159' 'Ground-based studies of emission-line variability' -- subject(s): Astrophysics, Optical data processing 'An introduction to active galactic nuclei' -- subject(s): Active galactic nuclei
P. W. J. M. Boumans has written: 'Methodology, Instrumentation and Performance, Part 1, Inductively Coupled Plasma Emission Spectroscopy' 'Line coincidence tables for inductively coupled plasma atomic emission spectrometry' -- subject(s): Inductively coupled plasma atomic emission spectrometry, Plasma spectroscopy, Tables 'Atomic Spectroscopy in the Netherlands and Countries Historically Linked to the Netherlands (Spectrochimica Acta)'
7390 m/s
Use dimensional analysis to answer this question.1 km = 1000 mMultiply 410 m by the relationship between meters and kilometers, so that meters cancel, leaving kilometers.410 m x 1 km/1000 m = 0.410 km
M. Slavin has written: 'Emission spectrochemical analysis'
Lines r and m are parallel or line r is line m continued