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Rather than do the math for you I will lay out how to do it and you can do the numbers yourself.

First, convert the volume of 25 gallons to milliliters:
Volume (gal) -> Volume (mL)


Second find the change in temperature:
T(high) - T(low) = dT (oC)


The calorie is defined as the amount of energy to raise one gram of water 1 degree Celsius.


Energy (calories) = Mass of Water (g) * dT (oC)


to find the mass of water convert volume to mass using the density equation D= m/V


Volume (mL) * Density (g/mL) = Mass of Water (g)


So the required energy is simply:


E (cal) =mass*dT


If you must report your answer in Joules (customary) you can convert calories to Joules using an established conversion constant.


E (cal) -> E (J)

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Q: What is the energy required to heat 25 gallons of water from 20 degrees Celsius to 80 degrees Celsius?
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How much heat energy would be required to bring a 15 kg block of ice from -20 degrees Celsius to steam at 120 degrees Celsius?

46389000 j


How many calories are required to convert 17g of ice at 0 degrees Celsius to liquid water at 32 degrees Celsius?

The simple beginning is that the definition of a calorie is "the energy required to raise the temperature of 1g of water 1°C." Therefore, the energy required to raise 17g of water 32°C: 17*32=544 cal. However, the question asked about ice. There is an extra bit of energy required for the change of physical state. The energy required to convert 1 gram of ice at 0°C to liquid water at 0°C is called the "latent heat" and is equal to about 80 cal. To convert 17g of ice, we multiply this together: 17g * 80cal/g = 1360 cal. So, we add this energy required for the change of state to the energy required to raise the listed quantity to the required temperature and we get 544 cal + 1360 cal = 1904 cal, assuming no heat is lost to the environment. I hope this clarifies some things.


What is an amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy?

The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.


Is the average kinetic energy of particle in a block of ice at 0 degrees the same as or different from the average kinetic energy of the particle in a gas-filles container at 0 degrees Celsius?

the same


How much heat energy in kilojoules is required to convert 41.0g of ice at -18.0 degrees C to water at 25.0 degrees C?

19.7 kJ

Related questions

How much energy is required to transform solid water at 0 degrees Celsius to liquid at 0 degrees Celsius?

80cal/g


How much energy is required to raise the temperature of 3 G of silver from 15 degrees Celsius to 20 degrees Celsius?

3.50 J


How much energy is required to raise the temperature of 3 kg of lead from 15 degrees celsius to 20 degrees celsius?

1935 J (apex)


How much energy is required to change 80g of ice at -30 degrees celsius to steam at 140 degrees Celsius?

E = m c (delta)T


How many joules of energy are required to raise the temperature of 74g of water from 20 degrees to 70 degrees celsius?

15480.80


How much heat energy would be required to bring a 15 kg block of ice from -20 degrees Celsius to steam at 120 degrees Celsius?

46389000 j


What energy unit is defined as the heat required to raise one kilogram of water by one degrees celsius?

I believe it is Calorie.


How much energy is required to raise the temperature of 3 kg of lead from 15 to 20 degrees of celsius?

1935 J (apex)


True or false a calorie is the amount of heat energy required to raise the temperature of 1 g of water 2 degrees C?

false its 1 degrees Celsius


How much energy is required to raise 21kg of water by 2 degrees Celsius?

21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.


Explain whether your body gains or loses thermal energy if your body temperature is 37 degrees Celsius and the temperature around you is 25 degrees Celsius?

25degres celsius has more thermal energy


What has more energy a bath full of water at 55 degrees celsius or a kettle full of water at 100 degrees celsius?

A normal bath full of water. Sorry but this depends on units of energy that you are familiar with-. I will use caldepending where you are taug The enery required to raise the temperature of the a 1kg of water in a kettle from zero degrees to 100 is 100 kilocalories The bath contains more at least 20 kg of water, and the energy required to raise the temperature of that volume of water by 55 degrees is 20 X 55 = 1100 kcals