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uh2
mg+ 2e
M + ionization energy à M1+ + e- M + ionization energy à M1+ + e-
First off, you have the equation written wrong... those are Ls not Is. so it's Al2(CO3)3 + ZnCl2 = ZnCO3 + AlCl3 The balanced form of that equation is Al2(CO3)3 + 3 ZnCl2 = 3 ZnCO3 + 2 AlCl3 So the coefficients are 1,3,3,2
H2CO3---------- 2 H+ + (CO3)2-
CH3CH2NH2+H2O⇌CH3CH2NH3++OH−
uh2
a=b=c
The chemical equation is: Ca2+ + (CO3)2- + 2H+ + 2(NO3)- = Ca2+ + 2(NO3)- + (CO3)2- + 2H+
mg+ 2e
M + ionization energy à M1+ + e- M + ionization energy à M1+ + e-
The chemical equation is:Al2(CO3)3 + 3 ZnCl2 = 2 AlCl3 + 3 ZnCO3
The balance equation is HI(aq) + H2O(l) ==> H3O^+(aq) + I^-(aq)
First off, you have the equation written wrong... those are Ls not Is. so it's Al2(CO3)3 + ZnCl2 = ZnCO3 + AlCl3 The balanced form of that equation is Al2(CO3)3 + 3 ZnCl2 = 3 ZnCO3 + 2 AlCl3 So the coefficients are 1,3,3,2
Hg(g) -> Hg^+(g) + e^-
The equation for the ionization of hydrochloric acid is as follows: HCl(aq) + H2O(l) --> H3O+(aq) + Cl-(aq) Note that 'free' protons, H+, do not exist in aqueous solution, and thus it is more proper to illustrate the proton transfer to water, instead of simply dissociating the acid into ions.
A. In order to achieve a balanced chemical equation of Al2(CO3)3 + 3 ZnCl2 = 2 AlCl3 + 3 ZnCO3, it is necessary to allow coefficients to each compound in such a way that the quantity of atoms is equal on both sides of the equation. Here's how we can balance it: Al2(CO3)3 + 3 ZnCl2 = 2 AlCl3 + 3 ZnCO3. The coefficients for the compounds are as follows: Al2(CO3)3 + 3 ZnCl2 = 2 AlCl3 + 3 ZnCO3. The balanced equation is: 1 Al2(CO3)3 + 3 ZnCl2 = 2 AlCl3 + 3 ZnCO3.