There are an infinity of lines passing through the point whose coordinates are (2,2), each with a different slope [gradient].
The equation of the line will be of the form (y - 2) = m*(x - 2) where m is the gradient.
It is the locus of all points whose coordinates satisfy the equation of the line.
By substitution
-4x + 9y = 0 is the equation of a line in the Cartesian plane and the coordinates of any of the infinite number of points on that line will satisfy the equation.
It's a linear equation in two variables . . . 'g' and 'p'. The graph of this equation is a straight line. The coordinates of every point on the line are a solution of the equation. There are an infinite number of them.
Subtract the equation of one line from the equation of the other
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
y + 4x = 2
It is the locus of all points whose coordinates satisfy the equation of the line.
Substitute the coordinates of the point into the equation of the line. If the equation is still valid then the point is on the line; if not then it is not.
(y -y1)=(x -x1)(y2 -y1)/(x2 -x1) defines the line containing coordinates (x1,y1) and (x2.y2).
By substitution
-5
-4x + 9y = 0 is the equation of a line in the Cartesian plane and the coordinates of any of the infinite number of points on that line will satisfy the equation.
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9x = 10x+7
It's a linear equation in two variables . . . 'g' and 'p'. The graph of this equation is a straight line. The coordinates of every point on the line are a solution of the equation. There are an infinite number of them.
Subtract the equation of one line from the equation of the other
Substitute the x coordinate into the equation for x and calculate y. If the formla gives the same y value as the coordinates, the point is on the line. If it is diffent, it is not on the line.