the equation when you mix silver nitrate and ammonium chloride is given as follows.It forms the whitish insoluble silver chloride AgCl.The precipiate is white in color.Its a doub
le displacemeent reaction.
NH4Cl + AgNO3 ------- AgCl ( s ) + NH4NO3
NH4Cl (aq) + AgNO3 (aq) => AgCl (s) + NH4NO3 (aq).
A white precipitate of silver chloride (AgCl) is formed.
87
the chemical equation for beryllium chloride reacts with silver nitrate in water to form beryllium nitrate and silver chloride can be written as follows .BeCl2 +2 Ag NO3 -> Be (NO3) 2 +2AgCl.A balanced equation has equal numbers of each type of atom on each side of the equation.
NaCl+AgNO3=NaNO3+AgCl Because all the elements in this equation have a +1 or -1 charge, no coefficents are needed
The silver in the Silver Nitrate precipitates the chloride ions out of the ammonium chloride solution, leaving Ammonium Nitrate in solution and a Silver Chloride solid.
If the silver nitrate and ammonium chloride are both in solution when mixed, the very sparingly soluble silver chloride precipitates as a solid, leaving ammonium nitrate in the solution.
NH4Cl (aq) + AgNO3 (aq) => AgCl (s) + NH4NO3 (aq).
- Dissolve ammonium chloride in water.- Add some crystals of silver nitrate and stir.- A white precipitate of silver chloride is formed.
(NH4)NO3 + AgNO3 --> (NH4)NO3 + AgNO3
A white precipitate of silver chloride (AgCl) is formed.
The addition of silver nitrate solution produces white precipitates of silver chloride which are soluble in ammonium hydroxide or liquid ammonia.
87
the chemical equation for beryllium chloride reacts with silver nitrate in water to form beryllium nitrate and silver chloride can be written as follows .BeCl2 +2 Ag NO3 -> Be (NO3) 2 +2AgCl.A balanced equation has equal numbers of each type of atom on each side of the equation.
Ammonium iodide is NH4I Silver nitrate is AgNO3
This equation is 3 BaCl2 + 2 Ag3PO4 -> Ba3(PO4)2 + 6 AgCl.
NaCl+AgNO3=NaNO3+AgCl Because all the elements in this equation have a +1 or -1 charge, no coefficents are needed