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Q: What is the equations of interaction of laser with uranium vapor?
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What has the author O H Krikorian written?

O. H. Krikorian has written: 'Recommended values for the vapor pressure of uranium' -- subject(s): Uranium, Vapor pressure


What is the laser interaction with uranium vapor?

You are speaking to atomic vapor laser isotope separation of 235U from 238U, and it's a "high tech" solution to the problem of enriching uranium. The process of atomic vapor laser isotope separation goes by the acronym AVLIS. Let's do a short review, then hammer the answer onto WikiAnswers. Ready? Buckle up. It is 235U that is fissile, but it is 238U that comprises over 99% of all uranium. Bummer. But how do you separate uranium from uranium? Good question, and that's the problem. We've used the difference in the mass of the different isotopes to do it mechanically. If we combine uranium with fluorine to make a gas and then spin it, the lighter 235U floride can be differentially "spun out" and can be separated with careful manipulation of a "gate" control. This is what was done at Oak Ridge, and continues to happen around the world. That's why you hear all that talk about centrifuges when the international nuclear investigators are poking around in someone's backyard. Enriched uranium us used as fuel and as weapons material. Fast forward to now. What if there was a way to selectively ionize one of the isotopes? What if we could do that with a laser? What if we took a bunch of uranium and streamed it down an evacuated tube and applied a magnetic field across the path of travel of the uranium? And then precisely tuned a (dye) laser to do the ionization? What if we could get it to deliver just the right amount of energy to just the 235U atoms to kick an electron up and away leaving a positively charged ion? And the ions suddenly felt the effects of the magnetic field they were moving in? And then the ions were forced to veer off the path because a charged particle moving in a magnetic field experiences acceleration? And that left the rest of the uranium, the 238U, to fly on down the tube unaffected? Then picked off the deflected 235U ions and allowed them to recombine with an electron to become neutral? And collected them as refined 235U? Would that work? Yup. And that's what we do. Got a link below to the Wikipedia article on this refining process.


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What has the author D J Gaffen written?

D. J. Gaffen has written: 'Application of a Lagrangian dispersion model to environmental problems' -- subject(s): Mathematical models, Air, Lagrange equations, Pollution 'Observed annual and interannual variations in tropospheric water vapor' -- subject(s): Atmospheric Water vapor, Observations, Water vapor, Atmospheric


How does the vapor pressure of water at 10 degrees celsius with its vapor pressure at 50 degrees celsius?

Do you mean, how does the pressure of water vapor at 10˚C compare with its pressure at 50˚C?The vapor pressure of water is the pressure at which steam is saturated. Above this pressure, the water would begin to condense. In a gas mixture saturated with water vapor, the vapor pressure is equal to the partial pressure. The vapor pressure is a function of temperature. Many equations of state can predict vapor pressures of liquids but the best ones are also rather complex and require considerable expertise to use. For most purposes, there are several simpler empirical equations which can estimate the vapor pressures of liquids with sufficient accuracy for most purposes.One of the simplest is the Antoine equation which has the form:log10Pvap = A - B/(C+T) where the Pressure (P) is in mmHg and the Temperature (T) is in °C.For water in the range from 1 °C to 100 °C, the constants have the values:A = 8.07131B = 1730.63C = 233.426Using these values, the vapor pressure of water can be estimated as:Pvap(@10 °C) = 9.158817 mmHgPvap(@50 °C) = 92.29989 mmHg... so the vapor pressure of water at 50 °C is roughly 10 times the vapor pressure at 10 °C.


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How can you determine the pressure of a fluid when two fluids of different pressures are mixed?

Assuming by pressure you mean vapor pressure there are several methods. Raoult's law states that the mixture vapor pressure will be the sum of the mole fractions multiplied by the pure component vapor pressures. The following is the mathematical expression of Raoult's law in its simplest form:P= x1*P1sat + x2*P2satP= mixture vapor pressurex1= liquid phase mole fraction of component 1x2= liquid phase mole fraction of component 2P1sat= saturation pressure (aka vapor pressure) of pure component 1P2sat= saturation pressure (aka vapor pressure) of pure component 2The Psat valves can be easily determined by using Antoine's equation and the corresponding constants for the desired materials.This assumes that the two fluids are an ideal mixture which is not the case for many fluids. Improvements to Raoult's law can be made by multiplying by the liquid phase activity coefficients. The equation will then look as follows:P= x1*P1sat*gamma1 + x2*P2sat*gamma2gamma1= liquid phase activity coefficient of pure component 1gamma2= liquid phase activity coefficient of pure component 2These activity coefficients may be computed by a number of methods including the Van Laar Equations, Margules Equations, Wilson Equations, or NRTL equations.