The factors are : (x² + 3) and (x + 5). Here's how I got that:
I plotted it and found it crosses the x-axis at x = -5. Substituting x = -5 verifies that -5 is a root. So one of the factors is (x + 5).
Using long division: (x³ + 5x² + 3x + 15)/(x+5) = x² + 3.
(x + 5)(x^2 + 3)
(5x + 2)(x + 1)
18 because, 5x2=10 10+8=18! Your welcome. It's not a problem at all. I love math!
5x2-16x+12 = (5x-6)(x-2) when factored
Yes. If you add, subtract or multiply (but not if you divide) any two polynomials, you will get a polynomial.
I am assuming this is: .2x4 - 5x2 - 7x, which would be a Quartic Polynomial.
False
The GCF is 5x2
(5x + 2)(x + 1)
18 because, 5x2=10 10+8=18! Your welcome. It's not a problem at all. I love math!
5x2-16x+12 = (5x-6)(x-2) when factored
(5x - 1)(x + 6)
True.
x3 + 5x2 - x - 5 = (x2 - 1)(x + 5) = (x + 1)(x - 1)(x + 5)
Yes. If you add, subtract or multiply (but not if you divide) any two polynomials, you will get a polynomial.
5x2 + 3x - 1 does not have rational factors.
= 5x2+70-16+9x-2 = 5x2+9x+52 = 5x2+9x1+52 This implies coefficient of degree 1 is 9. Ans.
I am assuming this is: .2x4 - 5x2 - 7x, which would be a Quartic Polynomial.