i) leakage flux is those flux which goes through the air and linkage flux is those flux whose go through the cell. ii)leakage flux is the loss at flux but linkage flu is warning flux. iii)leakage flux is cause of eddy current loss and linkage flux is case of copper loss.
As per transformer equation,E=4.44 * freq * flux * Turns.So E/ freq =Flux. So when a transformer is designed for 60Hz ,it CANNOT be operated at 50Hz and if operated may create heating effects and core saturation etc. Because E/60< E/50. However the converse condition is true i.e. a 50 HZ transformer can be used for 60Hz application Because E/50>E/60
light speeeed mofos
Basically useful fluke is the flux that flows with in the magnetic circuit of an armature. That is why when there is an air gap the flux enters the armature which makes it useful flux! Hope that answers your question!
EMF equation of DC GeneratorE = (ΦNPZ) / (60 * A)where,E = e.m.f induced in any parallel path in armatureΦ = flux per pole in weberN = armature rotation in revolutions per minute (r.p.m)P = No.of generator polesZ = total number of armature conductorsA = No.of parallel paths in armature
E E. O'Brien has written: 'On the flux of heat through laminar wavy liquid layers' 'On the flux of heat through laminar thin films'
Scalar
the flux goes about 95 km with a lipo battery.
Then the leakage flux will be reduced as leakage flux is iversely propertional to window factor i,e height to width ratio of the window. As height is more & width is less then the leakage flux ll travel through low reluctance path i,e core itself and it adds with the main flux or working flux.
acc. to gauses law..flux is equal to total charge/e or Q/e as there are six sides of the cube so flux through one surface will be Q/6e
i) leakage flux is those flux which goes through the air and linkage flux is those flux whose go through the cell. ii)leakage flux is the loss at flux but linkage flu is warning flux. iii)leakage flux is cause of eddy current loss and linkage flux is case of copper loss.
The HPI E-Firestorm does about 20 mph. The HPI E-Firestorm Flux does 44 mph. The Nitro firestorm rtr does 48mph
Using the Gauss' Law of Magnetism We know total flux will be zero flux(top)+flux(bottom)+flux(curved side)=0 ------- (a) flux(bottom)= -25e-3 (GIVEN) (-ve shows inward direction) flux(top)=B*A=(1.6e-3)*[3.14*(0.12)^2]=2.304e-5 Put the values in eq (a) you'll get flux(curved side)= +24.97e-3 (+ve shows direction is outward)
The Ratio of the total flux ( flux in iron path) to the useful flux (flux in air gap)
E 6013 E - Electrode 60- 60000 psi Tensile strength 1 - All position 8 - Basic lime / Iron powder flux
when a current flow through the coil then flux produced around the coil . if the flux linked same produced coil only then the flux is said to be leakage flux. flux produced by one coil ,but linked with another coil then the flu is said to be mutual flux.
when a current flow through the coil then flux produced around the coil . if the flux linked same produced coil only then the flux is said to be leakage flux. flux produced by one coil ,but linked with another coil then the flu is said to be mutual flux.