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No. There is no outward force exerted in circular motion. Inertia is the reasoning. For example, if your in a car going around a roundabout than you are going one way but the car is going the other hence Inertia is present.
Work is force exerted over a distance. If I pushed on my car really hard and it did not move, no work was done. If my car started going without any force being exerted on it, which would be miraculous, no work would have been done.
Going back to basic physics, motion results from acceleration, and acceleration equals force divided by mass. The force exerted by magnetic fields is described by Coulomb's Law.
Gravity adds a force (kgs) going downhill = sin (incline angle) * mass vehicle (kgs) and detracts the force when going uphill (same equation)
The more the vehicle weighs, the harder the brakes must work to stop it and the more distance it will need to stop the vehicle. However, large trucks can brake easier with more weight because weight adds friction which helps to stop the vehicle. This still doesn't fully compensate for the total stopping distance needed for a large vehicle. Basicly what he means is the heavier the vehicle the more friction it can create(slow it down) but it can add to the forward force iswell Or more precisely, the force of the vehicle going forward because of it's mass is still greater than the force of friction helping the vehicle slow down.
What force is act when ball is going to be thorn
If it's going at a constant speed then it is not accelerating. To accelerate would mean to have a rate of change for speed in some direction. If the ball is going outward while traveling at a constant speed due to centrifugal force then it is accelerating. If it's going inwards due to some ground angle then it is also accelerating. From Newton's laws we know that to have a circular motion, an object must be subject to a force directed to the centre of the structure and is accelerating in that direction. This centrifugal force, exerted by the structure to the ball, is opposite in direction and magnitude to the 'fictitious' centrifugal force.
g force is the force exerted on a body in the opposite direction to which said body is accelerating. if you're on a rollercoaster and your going not too fast and you suddenly change direction and accelerate quickly, you get pushed back into your seat. g force gets its name as 1g is the equivilent of the force of gravity on the earths surface. That's why when individuals experience g forces greater than 1 or 2, they experience a heavy, weighty feeling and do indeed for a brief moment weigh heavier.Sudden Change In Direction
When you "PUSH" then you are going against "Gravitational Force" but when you are "PULLING" then you are going against force.
Yes because if the car in front of you was going faster, the distance between the vehicle your in and the one in front of you would grow but, if the car was going slower than the speed your going, the vehicle will become closer. :)
The grip of a tire is due to the force of friction, and the force of friction is directly proportional to the weight of the vehicle on the tire. On a level road, the weight of any body is vertically down, and this results in a high value of weight pushing down on the tire, which gives us high value of friction and strong grip. By comparison, when going uphill or downhill, the weight of any vehicle is resolved into two components. One of the components will be a "down" component, but it will not be as great as the actual weight of the vehicle on level ground. This will result in a lower force of friction which results in a more loose grip of the tires.
gravitational force is the force that goes on to the moon.