BaBr2
Ba + SO4 will give you BaSO4 Ba + Br will give you BaBr2The first equation is barium sulfate and the second one is barium bromide.
The formula for barium bromide is BaBr2. This compound consists of one barium ion (Ba^2+) and two bromide ions (Br^-).
BaF2, which is called barium fluoride.
Barium bromide is an inorganic compound composed of barium and bromine, with the chemical formula BaBr2. It is a white crystalline solid and is commonly used in a variety of applications, including as a precursor in organic synthesis and in the production of specialty glass.
The compound with the formula Ba(CN)2 is barium cyanide. It is an inorganic compound composed of a barium cation (Ba2+) and two cyanide anions (CN-).
A solution of barium bromide would be neutral since barium bromide is a salt that dissociates into barium ions and bromide ions in water. Neither of these ions will significantly affect the pH of the solution.
Yes, barium bromide is soluble in water. When it dissolves in water, it dissociates into barium ions (Ba2+) and bromide ions (Br-), resulting in a clear solution.
CaBr2 is calcium bromide. Calcium bromide is a form of calcium salt hydrobromic acid and is primarily used in drilling fluid.
The equation of the reaction is BaBr2 + 2 AgNO3 -> 2 AgBr + Ba(NO3)2. Therefore, exactly as many bromide ions from barium bromide must be supplied to precipitate any particular number of silver ion from silver nitrate. From the definition of molarity, 100 ml of 52 M solution contains 5.2 moles (preferably called "gram formula units") of silver nitrate. The gram formula unit mass of silver nitrate is 169.87, and each gram formula mass contains equal numbers of silver and of nitrate ions. Therefore, 5.2 gram elemental masses of bromide ions will be required for the precipitation. This amount of bromide ions can be supplied by 5.2/2* or 2.6 gram formula masses of barium bromide, and the gram formula unit mass of barium bromide is 297.14. Multiplying this number by 2.6 shows that 7.7 X 102 grams of barium bromide, to the justified number of significant digits, will be needed.
To write the formula for barium bromide (BaBr₂) as a chemical equation, you need a reaction. For instance, the reaction between barium chloride (BaCl₂) and sodium bromide (NaBr) would form barium bromide and sodium chloride (NaCl): BaCl₂ + 2NaBr → 2NaCl + BaBr₂.
Ba+2 Br-1 -----> these are the ions and their chargesBa+2 Br+1 Br+1 ----> the charges must add to zero, so one positive Br ion is added to cancel out the +2 Ba ionBaBr2 ------> simplifyName: Barium bromide
The chemical formula for the compound formed between barium and bromine is BaBr2. In this compound, barium forms a +2 cation (Ba^2+) and bromine forms a -1 anion (Br^-), resulting in the formula BaBr2.