It would be: PbI2
The correct formula for the product of lead(II) nitrate reacting with sodium iodide is lead(II) iodide, which has the formula PbI2. This is because lead(II) ions from lead(II) nitrate react with iodide ions from sodium iodide to form lead(II) iodide as the product.
Formula: PbO
Formula: PbS
This chemical formula is Pb3P2.
PbBr2
Lead(II) Chromate = PbCrO4
Pb(HSO4)2.
It is aprecipitate chemical reaction.The chemical equation of aluminum iodide and leadII acetate is given as follows.. 2AlI3(aq) + 3Pb(C2H3O2)2(aq) --> 3PbI2(s) + 2Al(C2H3O2)3(aq).The above is a balanced equation.
The chemical formula of lead(II) nitrate is Pb(NO3)2.
The chemical formula of lead(II) nitrate is Pb(NO3)2.
BaI2 is the chemical formula for Barium Iodide.
Formula: AuI