there is'nt one sorry
The compound formed when lead reacts with iodine is lead(II) iodide, with the chemical formula PbI2.
Lead (II) iodide, which has PbI2 as its chemical formula, exists only this way and not in the form PbI4 as someone might guess. Though lead has a +2 and a +4 for its oxidation states, iodine is too weak an oxidizer to form the second lead-iodine compound. This stuff is toxic because of the lead, and you can read more about it by using the supplied link to the Wikipedia article.
The chemical formula for lead (II) iodide is PbI2. It is composed of one lead (Pb) atom and two iodine (I) atoms.
The correct formula for the product of lead(II) nitrate reacting with sodium iodide is lead(II) iodide, which has the formula PbI2. This is because lead(II) ions from lead(II) nitrate react with iodide ions from sodium iodide to form lead(II) iodide as the product.
The chemical formula for lead II iodide is PbI2, where Pb represents lead and I represents iodine. Lead II iodide is a yellow crystalline solid that is insoluble in water.
The formula for bromine is Br2 and the formula for iodine is I2.
The formula of iodine fluoride is IF3.
The formula for iodine water is I2 (molecular iodine) dissolved in water.
IBr7 is the formula for iodine heptabromide.
The formula for iodine oxide is ( I_2O_5 ).
I2
The chemical formula for iodine trifluoride is IF3.