If the area you're referring to is the cross-sectional area of the conductor: you can think of the cross-sectional area of a wire as the thickness of that wire. If you bundled two wires together in parallel, that would be a bit like having one, thicker wire, wouldn't it?
So increasing the area is analogous to adding more pathways for current to travel in parallel. Metals carry current on their surface, but also through electron "bands" in their interior -- increasing area means adding more bands = adding more pathways. And adding more pathways reduces resistance.
There is indeed a relationship between the length and cross-sectional area of a conductor and its resistance, but not with its resistivity.
Resistance is directly-proportional to the length, but inversely-proportional to the cross-sectional area, of a wire.
Resistivity, on the other hand, is a constant for a particular metal and is independent of the conductor's dimensions.
R = rho*L/A whereR is the resistance of a conductor of uniform cross section,
rho is the electrical resistivity of the conductor,
L is its length and
A is the cross-sectional area.
resistance of the wire is inversely proportional to area.R=rL/A,where r is the resistivity,l being the length,and R be the resistance
Resistance = rho x length / areaWhere:
rho is the resistivity (a material-specific property)
length... well, that's the length
area is the cross-sectional area
Cell constant(C) = Resistance(R) X Specific Conductivity(K)
Resistance is directly proportional to the resistivity and length of the conductor, and inversely-proportional to its cross-sectional area. As resistivity is affected by temperature, we can say that temperature indirectly affects resistance.
L1-L0=(RESISTANCE*AREA)/RESISTIVITY where L1=INIIAL LENGTH and L2=FINAL LENGTH
The relation between bending moment and the second moment of area of the cross-section and the stress at a distance y from the neutral axis is stress=bending moment * y / moment of inertia of the beam cross-section
I think the equation you are looking for is Resistance (ohms) = Resistivity * Length / Area or R=p*L/A. This is the resistance of a circular wire with cross-section of A, length of L, and material with resistivity p. So to get area: Area = Resistivity * Length / Resistance.
Force = Pressure x Area
It can't be done. You must also know at least any one of the following: Perimeter Relation between length and breath Relation between Area and length Relation between Area and breath Relation between perimeter and Area Breath and so on...........
We can reduce the supply voltage from the ohms law relation.......v=ir... resistance is directly proportional to supply voltage...or.....we can control the resistance by the relation by R is directly proportional to l/a l=length a=area
by ASR do you mean Area Specific Resistance?
Pressure = force / area
In relation to the area of a circle: pi*radius^2
There is no direct relation between the area of a sector and the length of an arc. You must know the radius (or diameter) or the angle of the sector at the centre.
R is the electrical resistance,A is the cross-sectional area,l is the length of the piece of material.
Resistance (Ohms) = Voltage (v) / Current (I)
The basic relation to calculate resistance tells us: R = rho*l/A with R = resistance [Ohm] rho = resistivity [Ohm*meter] l = length [m] A = surface area [m^2] So, the resistance (given a certain resistive material) merely depends on the ratio between the length and the surface area of a resistor. Resisotrs tend to be bigger if they have to dissipate more power, for mor heat needs to be lost.
R is the electrical resistance,A is the cross-sectional area,l is the length of the piece of material.
Cell constant(C) = Resistance(R) X Specific Conductivity(K)