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If the area you're referring to is the cross-sectional area of the conductor: you can think of the cross-sectional area of a wire as the thickness of that wire. If you bundled two wires together in parallel, that would be a bit like having one, thicker wire, wouldn't it?

So increasing the area is analogous to adding more pathways for current to travel in parallel. Metals carry current on their surface, but also through electron "bands" in their interior -- increasing area means adding more bands = adding more pathways. And adding more pathways reduces resistance.

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13y ago
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10y ago

There is indeed a relationship between the length and cross-sectional area of a conductor and its resistance, but not with its resistivity.

Resistance is directly-proportional to the length, but inversely-proportional to the cross-sectional area, of a wire.

Resistivity, on the other hand, is a constant for a particular metal and is independent of the conductor's dimensions.

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7y ago

R = rho*L/A whereR is the resistance of a conductor of uniform cross section,

rho is the electrical resistivity of the conductor,

L is its length and

A is the cross-sectional area.

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14y ago

resistance of the wire is inversely proportional to area.R=rL/A,where r is the resistivity,l being the length,and R be the resistance

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7y ago

Resistance = rho x length / areaWhere:

rho is the resistivity (a material-specific property)

length... well, that's the length

area is the cross-sectional area

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Q: What is the formula of relation between resistance and area of a wire?
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