6.88 x 10 14 Hz
6.88 1014 Hz
The frequency of a photon with an energy of 4.56 x 10^19 J can be calculated using the formula E = hf, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J∙s), and f is the frequency. Rearranging the formula to solve for frequency, f = E/h, we get f = (4.56 x 10^19 J) / (6.626 x 10^-34 J∙s) = 6.88 x 10^52 Hz.
Energy per photon = (Planck's Konstant) x (Frequency)
Planck's Konstant (h) = 6.62606957×10−34 J·s
Frequency = energy per photon/h = 1.55 x 10-24/6.626 069 x 10-34 = 2.3392 GHz (rounded)
The energy of a photon can be calculated using the formula: E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency. Plugging in the values, the energy of a photon of yellow light with a frequency of 5.45 x 10^14 Hz would be approximately 3.6 x 10^-19 Joules.
The frequency of light is directly proportional to its energy. This means that higher frequency light (like blue or violet) carries more energy than lower frequency light (like red or yellow). This relationship is described by the equation E = h * f, where E is energy, h is Planck's constant, and f is frequency.
Since the wavelength times the frequency is equal to the speed of the wave, all you need to do in this case is divide the speed of light (in meters/second) by the frequency. The answer will be in meters.
The wavelength of a photon can be calculated using the equation: wavelength = Planck's constant / photon energy. Given the photon energy, you can plug in the values to find the corresponding wavelength.
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the photon. Plugging in the values for a 240 nm ultraviolet photon, the energy can be calculated as E = (6.626 x 10^-34 J·s * 3.00 x 10^8 m/s) / (240 x 10^-9 m) = 8.27 x 10^-19 J.
The energy of a photon can be calculated using the formula E = h * f, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of the photon. Thus, for a frequency of 5 x 10^12 Hz, the energy of the photon would be 3.31 x 10^-21 Joules.
The energy of a photon is given by E = hf, where h is the Planck's constant (6.626 x 10^-34 J·s) and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 6 x 10^12 Hz is approximately 3.98 x 10^-21 Joules.
The energy of a photon is given by the formula E = hf, where h is Planck's constant (6.626 x 10^-34 J s) and f is the frequency of the photon. So, for a photon with a frequency of 6 x 10^12 Hz, the energy would be approximately 3.98 x 10^-21 Joules.
The energy of a photon is given by E = hf, where h is Planck's constant (6.626 x 10^-34 J.s) and f is the frequency of the photon. Plugging in the values, the energy of a photon of red light with a frequency of 4.48 x 10^14 Hz is approximately 2.98 x 10^-19 Joules.
The energy of the electron increased by absorbing the photon with that frequency. Energy of a photon is directly proportional to its frequency, so a photon with a frequency of 4 x 10^15 Hz carries a specific amount of energy, which was transferred to the electron upon absorption.
The energy of a photon is determined by the equation E = hf, where E is energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency of the photon. First, calculate the frequency of the photon using the speed of light equation, c = λf. Then, substitute the frequency into the energy equation to find the energy of the photon.
The frequency of a photon with a wavelength of 488.3 nm is approximately 6.15 x 10^14 Hz. The energy of this photon is approximately 2.54 eV.
The frequency of a photon can be calculated using the formula E = hf, where E is the energy of the photon, h is Planck's constant (6.63 x 10^-34 J*s), and f is the frequency. Rearranging the formula to solve for frequency gives f = E / h. Plugging in the values, we find that the frequency of a photon with an energy of 3.38 x 10^-19 J is approximately 5.10 x 10^14 Hz.
the energy of a photon is h times f
The energy of a photon can be calculated using the formula E = hf, where h is Planck's constant (6.626 x 10^-34 J·s) and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 4 x 10^7 Hz is approximately 2.65 x 10^-26 Joules.
The energy carried by a photon can be calculated using the equation E = hf, where h is Planck's constant (6.626 x 10^-34 J·s) and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 5.71 x 10^14 Hz would be approximately 3.78 x 10^-19 Joules.
The energy of a photon is given by ( E = hf ), where ( h ) is the Planck constant and ( f ) is the frequency of the photon. Rearranging the formula gives ( f = E / h ). Plugging in the given energy value and the Planck constant, the frequency of the photon is approximately 3.01 x 10^22 Hz.