Energy of the photon = Planck's constant x frequency of the ultraviolet radiation
E = h x f
frequency of the ultraviolet radiation = speed of light / wavelength of the ultraviolet radiation
f = c/ lambda
E = 6.63 x 10-34 x 3 x 108 / 3 x 10-7 = 6.63 x 10-19 Joules
The energy of the electron decreased as it moved to a lower energy state, emitting a photon with a wavelength of 550 nm. This decrease in energy corresponds to the difference in energy levels between the initial and final states of the electron transition. The energy of the photon is inversely proportional to its wavelength, so a longer wavelength photon corresponds to lower energy.
The energy of a photon can be calculated using the formula E=hc/λ, where h is Planck's constant (6.626 x 10^-34 J*s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. Converting 663 nm to meters (1 nm = 1 x 10^-9 m), we get λ = 663 x 10^-9 m. Plugging in the values, we find the energy of the photon to be approximately 3.00 x 10^-19 Joules.
Short-wave ultraviolet light (UV-C, 100-280 nm) is best for viewing fluorescent minerals, as it provides the most intense fluorescence. Medium-wave ultraviolet light (UV-B, 280-315 nm) can also be used, but the fluorescence will be less intense. Long-wave ultraviolet light (UV-A, 315-400 nm) is not ideal for viewing fluorescent minerals as it may not excite the fluorescence as effectively.
The formula for frequency is f = c/lambda, where c is the speed of light in a vacuum, lambda is the wavelength in meters, and f is frequency in cycles per second. So, if the wavelength is 700.5 nm, the frequency is 4.28 E14 hertz.
The wavelength is 610 nm.
The energy of a photon can be calculated using the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. Plugging in the values for a 170 nm ultraviolet photon gives an energy of approximately 7.3 eV.
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
The energy of a photon can be calculated using the formula E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J*s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the photon in meters. First, convert the wavelength to meters (130 nm = 130 x 10^-9 m), then plug the values into the formula to find the energy. The energy of an ultraviolet photon with a wavelength of 130 nm is approximately 1.52 x 10^-18 Joules.
The energy of a 500 nm photon is 3.1 eV (electron volts). This is a unit of measure used to represent the energy of a single photon. To put this into perspective, a single photon of visible light has an energy of 1.8 to 3.1 eV, and a single photon of ultraviolet light has an energy of 3.1 to 124 eV. The energy of a 500 nm photon can be calculated by using the following equation: E = hc/ Where: E = energy of the photon (in eV) h = Planck's constant (6.626 * 10-34 Js) c = speed of light (2.998 * 108 m/s) = wavelength of photon (in meters) Therefore, the energy of a 500 nm photon is calculated as follows: Convert the wavelength from nanometers to meters: 500 nm = 0.0005 m Insert the values into the equation: E = (6.626 * 10-34 Js) * (2.998 * 108 m/s) / (0.0005 m) Calculate the energy: E = 3.1 eVTherefore, the energy of a 500 nm photon is 3.1 eV.
The energy of a photon with a wavelength of 500 nm is approximately 2.48 keV.
The energy of a photon is given by E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. Plugging in the values, the energy of an ultraviolet photon with a wavelength of 1.18 nm is approximately 10.53 eV.
The frequency of a photon with a wavelength of 488.3 nm is approximately 6.15 x 10^14 Hz. The energy of this photon is approximately 2.54 eV.
The energy of this photon is 3,7351.10e-19 joules.
610 nm
Photon energy is proportional to frequency ==> inversely proportional to wavelength.3 times the energy ==> 1/3 times the wavelength = 779/3 = 2592/3 nm
Transition B produces light with half the wavelength of Transition A, so the wavelength is 200 nm. This is due to the inverse relationship between energy and wavelength in the electromagnetic spectrum.
The energy of the electron decreased as it moved to a lower energy state, emitting a photon with a wavelength of 550 nm. This decrease in energy corresponds to the difference in energy levels between the initial and final states of the electron transition. The energy of the photon is inversely proportional to its wavelength, so a longer wavelength photon corresponds to lower energy.