The formula for frequency is f = c/lambda, where c is the speed of light in a vacuum, lambda is the wavelength in meters, and f is frequency in cycles per second. So, if the wavelength is 700.5 nm, the frequency is 4.28 E14 hertz.
You mean the energy content of photon.
E = h c / L
Here h is Planck's constant = 6.626 * 10^-34 Js
c = speed of light = 3 * 10^8 m/s
And L = wavelength = 700 nm ie 7 * 10^-7 m
Plug and you get the energy of photon in Joule.
To convert the same in eV, we have to divide it by 1.602 * 10^-19
So required energy of each red photon = 1.773 eV
750 nm would be a very deep red, as it is right on the border between visible and infrared.
brown sh**
red
Shortest wavelength means the highest frequency, meaning the photons have the highest energy. That is color violet. The violet light colors the skin brown. Red light with lower energy photons cannot do that.
No, red is the longest wavelength of visible light, with the lowest frequency and the least energy. Violet light has the shortest wavelenght, with the highest frequency and the most energy (of visible light).
very nice answer.
Because of the differences in droplets sizes in which each size scatters specific wavelength of light which leads to scattering of all visible spetrume or what we see as a white color
5890
it is short wavelength
If it is between 390 and 700nm (nano meter) then yes.
Visible light has a wavelength of 400nm-700nm (from violet to red). Ultraviolet rays which starts immediately after the violet region of visible light have their wavelength from 10nm-400nm.(where nm means nano-meter)
No, the wavelength determines the color of the light. 700nm corresponds to red, 400nm to about purple, and in between are the rest of the visible colours.
4200K
Violet.
In the "visible" light it is violet.
4200 K
PAR- Photosynthetically Active Radiation- 400-700nm
Red light has the longest wavelength.
It alters the energy and colour of the light.
Your question is meaningless. Light is electromagnetic radiation and the colour of light depends on the wavelength of this radiation. There is no such thing as a "weak" wavelength.