it's not a statement, it's a function:
len= printf (format, ...more-parameters...);
It is a function.
#include <limits.h> if (1) { printf ("INT_MAX is %d\n", INT_MAX); printf ("LONG_MAX is %ld\n", LONG_MAX); }
syntax: for(initialization;condition;increment) { statements s1; statements s2; } #include<stdio.h> main() { int i,n=5; for(i=0;i<n;i=i+1) { printf("the number s are %d", i); } }
You can use any number of if staments within a for-loop, eg: for (i=0; i<10; ++i) { if (i=1) printf ("%d=1\n",i); }
printf() is a build-in function under the header file 'stdio.h' in a C programming language. In c++,the same function is accomplished by 'cout' . It is used to display strings enclosed between double quotes. Its syntax is printf("...string/sentences/characters...."); After execution,all the characters between the double quotes will be displayed on the output screen.
Printf function is used in c language. Printf is used to print something to the standard output. ex: printf ('welcome');
No. A violation in the syntax of a program statement is called a syntax error.
int main (void) { if(printf("Print whatever you want")) { } }
== == What is printf in c or prototype of printf with example (q) What is prototype of printf function ? Explain each term. Ans: Prototype of printf function is : int printf( const char *format ,…) Explanation of each term : Parameter of printf function is : (three continuous dots) : It is called ellipsis. It indicates the variable number of arguments. Example of ellipsis: #include void ellipsis(int a,...); void main() { int a=5,b=10; clrscr(); ellipsis(a,b); getch(); } void ellipsis(int a,...) { printf("%d ",a); } Output:5 So printf function can have any number of variables as an argument.
in stdio.h:extern int printf (const char *fmt, ...);
The only language, which has remark-statement, is BASIC. Syntax: REM any text
I believe, you can use C-function - printf().