Trihybrid Cross of AaBbCc x AaBbCc
64 results
Genotypic ratio
1 AABBCC
2 AABBCc
1 AABBcc
2 AABbCC
4 AABbCc
2 AABbcc
1 AAbbCC
2 AAbbCc
1 AAbbcc
2 AaBBCC
4 AaBBCc
2 AaBBcc
4 AaBbCC
8 AaBbCc
4 AaBbcc
2 AabbCC
4 AabbCc
2 Aabbcc
1 aaBBCC
2 aaBBCc
1 aaBBcc
2 aaBbCC
4 aaBbCc
2 aaBbcc
1 aabbCC
2 aabbCc
1 aabbcc
1:2:1:2:4:2:1:2:1:2:4:2:4:8:4:2:4:2:1:2:1:2:4:2:1:2:1
Phenotypic Ratio
27 ABC
9 ABc
9 AbC
9 aBC
3 Abc
3 aBc
3 abC
1 abc
27:9:9:9:3:3:3:1
27:9:9:9:3:3:3:1
3:1 The genotypic ratio is 1:2:1
16:9:9:3 get it?
Green is dominant, and albino is recessive. If you cross heterozygous plants, you will end up with about a 3:1 ratio of green to albino.
a ratio that was at first incorrect but has been fixed
The first person to recognize the total ratio of the number atoms is the same as the total ratio of the ratio of the mass is JOHN DALTON.This is also called the "Law of Multiple Proportion"
The ratio of 50 ml and 2 litre is?
Nominal Scale < Ordinal< Interval < Ratio
100/100
The phenotypic ratio is a 3:1 ratio.
1:1:1:1:1:1:1:1 ratio is the expected outcome of a heterozygous (BbGgCc) and a homozygous recessive (bbggcc) cross.
A cross between two heterozygous parents (eg. Gg X Gg) would result in a phenotypic ratio of 3 dominant : 1 recessive, and a genotypic ratio of 1GG:2Gg:1gg.GgGGGGggGggg
What is the ratio of heterozygous offspring to total offspring in the punnett square
A monohybrid cross is a cross between parents who are heterozygous at one locus; ... The results The wrinkled trait --- which had disappeared in his hybrid ...of them produced both types of seeds in the F3 and - once again - in a 3:1 ratio
1 homozygous dominant: 2 heterozygous: 1 homozygous recessive
The phenotypic ratio resulting from a dihybrid cross showing independent assortment is expected to be 9:3:3:1. This ratio is obtained when two heterozygous individuals are crossed for two traits that are independently inherited. The ratio represents the different combinations of phenotypes that can arise from the cross.
All you need to do is use a Punnet Square for this. You will get the following genotypical and phenotyical ratio from this cross: RrBb x RRbb = RRBb RrBb RRbb Rrbb In terms of phenotypical ratios, 50% of the offspring have a chance of showing R and B, and the other half have the chance of showing R and b.
Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
Green is dominant, and albino is recessive. If you cross heterozygous plants, you will end up with about a 3:1 ratio of green to albino.
The traits were recessive.