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All you need to do is use a Punnet Square for this. You will get the following genotypical and phenotyical ratio from this cross:

RrBb x RRbb =

RRBb

RrBb

RRbb

Rrbb

In terms of phenotypical ratios, 50% of the offspring have a chance of showing R and B, and the other half have the chance of showing R and b.

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13y ago
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9y ago

1:1:1:1

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Q: Perform the following cross rrgg x RrGg What is the phenotypic ratio?
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What is the phenotype ratio of a cross between a heterozygous male and female?

The phenotypic ratio is a 3:1 ratio.


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The phenotypic ratio resulting from a dihybrid cross showing independent assortment is expected to be 9:3:3:1. This ratio is obtained when two heterozygous individuals are crossed for two traits that are independently inherited. The ratio represents the different combinations of phenotypes that can arise from the cross.


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What is the phenotypic ratio of the?

Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.


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What is the phenotypic ratio of the F-2 generation of the monohybrid cross?

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What is the phenotypic ratio of the following dihybrid cross AaBb x AaBb?

These are the phenotypic ratios of each outcome: Dominant A and B: 9/16 Dominant A and recessive B: 3/16 Recessive A and dominant B: 3/16 Recessive A and B: 1/16


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What is the importance of a 9331 ratio in a monohybrid cross?

The phenotypic ratio expected from a monohybrid cross between heterozygotes is 3:1 (assuming complete dominance), with the genotypic ratio being 1:2:1. So, using tall = T, short = t and R = red, r = white as an example. A monohybrid cross of Tt X Tt would be expected to produce 3 tall plants and 1 short plant (phenotypic ratio 3:1), which would be 1 TT, 2 Tt and 1 tt (genotypic ratio 1:2:1). A dihybrid cross of heterozygotes is expected to produce a phenotypic ratio of 9:3:3:1. So the cross of TtRr X TtRr would be epected to have: 9 tall red, 3 tall white, 3 short red and 1 short white (phenotypic ratio) This is because each parent has 4 possible combinations of gametes (TR, Tr, tR and tr). There are therefore 16 combinations of gametes, providing a 9:3:3:1 phenotypic ratio. Both of these are probably best visualised using a punnett square (see link below).