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I don't quite understand why you mix "gravitation" and "weightless" in the question. The gravitational acceleration of Earth is 9.8 m/sec2 near the surface; further away, it will gradually decrease. The presence of air - if that is what you referring to - is quite irrelevant to the fact that there is gravitation.

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Q: What is the gravitational acceleration of earth in a weightless environment?
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Related questions

Does a body which orbits the earth became weightless?

A body in orbit is in free fall, so no weight would be experienced by it. It moves under gravity, but the gravitational force is exactly matched by its acceleration.

What is the planet earth's gravitational force?

This can be measured by the acceleration due to gravity at the surface. Earth's surface gravitational acceleration is about 9.8 m/s2

Why is the gravitational accleration of any object near Earth is the same?

The earth creates a gravitational acceleration field around the earth and objects in that field experience the same acceleration field.

What is the rate of acceleration of earth's center?

Earth's gravitational acceleration is approximately 9.8 m/s^2, or 1g.

What balances the gravitational attraction of the earth on a falling object?


Why an object becomes weightless in outer spaceaway from any planet or star?

Gravitational forces are much reduced by distance. Also, they would be fairly well balanced in all directions. However, there would probably still be some detectable gravitational force. The other definition of "weightless" is when an object is still in a gravitational field, but in "free fall". That's why astronauts orbiting Earth are "weightless".

Gravitational force decreases with distance. What does this mean for a space traveler who leaves earth in a spaceship?

While his ship is accelerating away from the Earth he will feel heavier as acceleration acts a lot like gravity. Upon decelerating he will begin to feel lighter, a lot lighter, until he is almost weightless.

What is the earth's gravitational constant?

At the Earth's surface, the acceleration due to gravity is 9.8 m/s2.

What determines the size of gravitational force?

The mass of the object the force is acting on, and the gravitational acceleration where the force is acting. F = m*g, where F is the gravitational force, m is the mass of the object and g is the gravitational acceleration (on Earth it is about 9.81ms-2)

What is the gravitational acceleration of an object on the surface of the earth?

At or near the surface of the earth, the acceleration due to gravity is 32 feet per second per second

Value of gravitational acceleration in centimeter per seconds squared?

On Earth, that is about 980.

How do I find the distance an object is from the earth with only it's mass and weight in it's current position?

You divide the mass by the weight, to get the gravitational acceleration. Then you use the fact that this gravitational acceleration, or gravitational field, is inversely proportional to the square of the distance. The distance should be calculated from the center of the Earth.