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100 inch/pounds
what is the torque specs and valve lash on a 24 hp Briggs
Get the model # and click the link I will post.
Cylinder Head Torque is 190 inch pounds or 22.0nm
122inch lb
The torque sequence for a single cylinder Briggs and Stratton engine horizontal shaft head is increments of 2's for hp and 1's for head bolts. That makes 11 head bolts for an 18 hp.
What spec do you need? need more info and include model and type off of engine cowling
Head Bolts should be torqued at 185 inch pounds
220 in-lbs
From the Briggs & Stratton literature you know torque at a specific RPM you can use math to calculate HP at that RPM. The Engine you are asking about has 11.5 lbs/ft of torque. Multiply 11.5 X 3060 RPM (measurement engine speed) then divide by 5250 (HP Factor). So the engine in question has 6.7 HP at 3060 RPM. This particular engine is normally run at 3600 RPM not 3060 as done in the testing. We must assume a little here but there are two approaches you can take. Substitute the run RPM for the test RPM in the formula and you get 7.5HP (assuming a flat torque curve) another approach, the Test RPM is 85% of the run RPM divide the 6.7HP by .85 and you get 7.8 HP. So What is it really? Without a copy of the torque curve you can't definitely say. But I would wager it would have been rated as an 8 or 8.5 HP in the old days. Remember this is the HP on the engine Shaft with no equipment attached. This would be a good engine for a 24" to 27" two stage snow blower. Torque x RPM / 5250 = HP
You need to specify the engine model/ series. It could be any where from 160in lbs. to 220 in lbs. or 35 ft lbs.
.007 on the intake and .011 on the exhaust.