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The horizontal velocity of the projectile (and the air resistance if known) will determine the horizontal distance traveled and the time required.
Do you really mean minimum distance? This would be achieved if the projectile went straight up and down, ie 90 deg from horizontal. Maximum distance would be obtained at 45 deg to horizontal.
range
The type of motion that describes the horizontal component of a projectile is horizontal projectile motion. It is influenced by the downward force of gravity.
Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.
The horizontal velocity of the projectile (and the air resistance if known) will determine the horizontal distance traveled and the time required.
Do you really mean minimum distance? This would be achieved if the projectile went straight up and down, ie 90 deg from horizontal. Maximum distance would be obtained at 45 deg to horizontal.
A trajectory of 45 degrees elevation gives the longest horizontal travel- (not taking air drag into consideration nor any aerodynamic properties of a projectile.
-- the initial horizontal speed of the projectile -- the time it remains in flight before it hits the ground
90
range
The horizontal distance will be doubled.
A trajectory is the angle made with the horizontal when a projectile is fired. Suppose the projectile is a cannon ball. Assuming air is frictionless, that cannon ball will travel the greatest distance if the trajectory is 45 degrees from horizontal.
The type of motion that describes the horizontal component of a projectile is horizontal projectile motion. It is influenced by the downward force of gravity.
its 45 degree
The optimal angle to fire a projectile if the objective is distance is 45 degrees. It follows that the distance traveled decreases whether the angle is increased or decreased from 45.
45 degrees to the horizontal will give the maximum flight time for a projectile. If a projectile was fired at 90 degrees to the horizontal, (straight upwards) the projectile will go straight upwards (ignoring the shape, form and aerodynamic properties of the projectile). Likewise if you were to fire a projectile at 0 degrees to the horizontal, the projectile would follow said course, IF gravity was not in effect; a projectile needs some form of vertical velocity to overcome gravity. Hence why 45 degrees will give you the longest distance and consequently flight time.