0
What is the initial velocity if you kick a rock off a bridge that is 450 meters high and it travels a horizontal distance of 32 meters before hitting the water below?
AnandaAdhikariVEVO
You kicked the rock with an initial velocity of 3.4 m/s.
Wiki User
∙ 12y ago
Add your answer:
Earn +20 pts
What is the value of constant horizontal velocity?
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
A projectile is thrown with an initial velocity which has a horizontal component of 4 m s What will be its horizontal speed after 3s?
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
Where A Particle Is Projected Along A Linear Plane. The Horizontal Component Of The Velocity Is Twice The Vertical Component What Is The Initial Magnitude Of The Velocity And The Angle At Which It Is?
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
What do you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
A shell is fired from the ground with an initial velocity of 1600m s at an angle of 64 to the horizontal What is the shells horizontal range?
If a shell is fired from the ground with velocity of 1600 m and an angle of 64 to the horizontal then it would have a horizontal rang of 55.0. This is considered math.
What is the value of constant horizontal velocity?
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
How do you find vertical and horizontal components when given the initial velocity?
If the initial velocity is v, at an angle x to the horizontal, then the vertical component is v*sin(x) and the horizontal component is v*cos(x).
A projectile is thrown with an initial velocity which has a horizontal component of 4 m s What will be its horizontal speed after 3s?
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?
Final velocity = Initial velocity +(acceleration * time)
Where A Particle Is Projected Along A Linear Plane. The Horizontal Component Of The Velocity Is Twice The Vertical Component What Is The Initial Magnitude Of The Velocity And The Angle At Which It Is?
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
A guy drove a car from a flat ground on top of a building and laded on the next one that's 100m away several floors down. If the car landed with an angle 30 degrees to x axis, find initial horizontal speed of car?
Initial horizontal velocity = ux (Note this velocity does not affect by gravity so stays the same throughout the jump) Initial vertical velocity = uy = 0 time to travel horizontal distance, t = (horizontal distance)/(horizontal velocity) t = 100/ux This is the same time the car takes to travel vertical distance. Using one of the equation of motion vertical landing velocity, vy = uy + gt vy = 0 + (9.81)(100/ux) vy = 981/ux angle of landing = 30° tan30° = vy/ux tan30° = (981/ux)/ux (ux)² = 981/tan30° ux = 41.22 m/s
What do you you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
What do you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
A shell is fired from the ground with an initial velocity of 1600m s at an angle of 64 to the horizontal What is the shells horizontal range?
If a shell is fired from the ground with velocity of 1600 m and an angle of 64 to the horizontal then it would have a horizontal rang of 55.0. This is considered math.
What kind of information is indicated by the graph of a landing site distance versus projectiles mass if the slope of the curve is zero?
Force = mass * acceleration Mass is only involved during the acceleration in the gun barrel , and is involved (with the explosive force) in translating to muzzle velocity. The horizontal distance travelled depends on the muzzle velocity and the incline of the barrel to horizontal. The curve will be parabolic even when the launch angle is 0 in which case the path will be negative (essentially going underground) 1. split launch velocity into horizontal and vertical vectors 2. using vertical velocity vector (initial velocity u), calculate (total) time to rise and fall back to ground using newtons equations. 3. multiply time by horizontal velocity vector to calculate horizontal distance travelled to landing site.
How do you find the initial velocity given only distance?
You cannot.
How do you find the final velocity given only distancetimeand initial velocity?
v = 2s/t - u where u=initial velocity, v=final velocity, s = distance and t = time
