You kicked the rock with an initial velocity of 3.4 m/s.
Increasing the initial horizontal velocity of an object would cause it to cover more horizontal distance in the same amount of time, leading to a longer horizontal range. The object would maintain the same vertical acceleration due to gravity, so it would still follow a parabolic trajectory but reach a farther horizontal distance before hitting the ground.
The horizontal distance traveled by a projectile is determined by the initial velocity of the projectile, the angle at which it was launched, and the time of flight. It can be calculated using the equation: horizontal distance = (initial velocity * time * cosine of launch angle).
To determine the initial velocity in projectile motion, you can use the equation v (x y) / t, where v is the initial velocity, x is the horizontal distance traveled, y is the vertical distance traveled, and t is the time taken.
it depends on the gravitational force of attraction of earth and air resistance. if we are neglecting air resistance, the max.horizontal distance is according to this formulae, V0/2 * sin (2theta) where V0 is the initial velocity theta is the angle with x axis and the projection.
To find Chris Bromham's initial velocity when he left the ground, you can use the horizontal distance he traveled, the time he was in the air, and the acceleration due to gravity. The equation to use is: horizontal distance = horizontal velocity * time in the air. By rearranging the equation to solve for the horizontal velocity, you can find Chris Bromham's initial velocity when he left the ground.
The horizontal distance traveled by a projectile is determined by the initial velocity of the projectile, the angle at which it was launched, and the time of flight. It can be calculated using the equation: horizontal distance = (initial velocity * time * cosine of launch angle).
Increasing the initial horizontal velocity of an object would cause it to cover more horizontal distance in the same amount of time, leading to a longer horizontal range. The object would maintain the same vertical acceleration due to gravity, so it would still follow a parabolic trajectory but reach a farther horizontal distance before hitting the ground.
To determine the initial velocity in projectile motion, you can use the equation v (x y) / t, where v is the initial velocity, x is the horizontal distance traveled, y is the vertical distance traveled, and t is the time taken.
it depends on the gravitational force of attraction of earth and air resistance. if we are neglecting air resistance, the max.horizontal distance is according to this formulae, V0/2 * sin (2theta) where V0 is the initial velocity theta is the angle with x axis and the projection.
To find Chris Bromham's initial velocity when he left the ground, you can use the horizontal distance he traveled, the time he was in the air, and the acceleration due to gravity. The equation to use is: horizontal distance = horizontal velocity * time in the air. By rearranging the equation to solve for the horizontal velocity, you can find Chris Bromham's initial velocity when he left the ground.
The horizontal motions of a projectile are independent of its vertical motion. This means that the horizontal velocity remains constant and unaffected by gravity. Additionally, the horizontal distance traveled by a projectile is determined by the initial horizontal velocity and the time of flight.
Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.
The horizontal component of the initial velocity of the ball is the velocity in the horizontal direction at the moment the ball is launched. It represents the speed and direction at which the ball is moving side-to-side.
To determine how far a projectile travels horizontally, you need to know the initial velocity of the projectile, the angle at which it was launched, and the acceleration due to gravity. Using these values, you can calculate the time of flight and then multiply it by the horizontal component of the initial velocity to find the horizontal distance traveled.
If "range" means that the shooter and the target are on the same level: quadrupled (if airesistance can be neglected). It takes twice the time until gravity "eats up" vertical velocity and during that time the projectile moves with double horisontal velocity. But if you shoot horisontally from a cliff at double velocity the flighttime will be the same and the range only doubled.
If the initial velocity is v, at an angle x to the horizontal, then the vertical component is v*sin(x) and the horizontal component is v*cos(x).
Using the projectile motion equations and given the initial velocity and angle, we can calculate the time the shell is in the air. Then, we can find the horizontal range by multiplying the time of flight by the horizontal component of the initial velocity. The horizontal range in this case is about 1056 meters.