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What would happen if the initial horizontal velocity was increased?

Increasing the initial horizontal velocity of an object would cause it to cover more horizontal distance in the same amount of time, leading to a longer horizontal range. The object would maintain the same vertical acceleration due to gravity, so it would still follow a parabolic trajectory but reach a farther horizontal distance before hitting the ground.


What is the horizontal distance traveled by a projectile?

The horizontal distance traveled by a projectile is determined by the initial velocity of the projectile, the angle at which it was launched, and the time of flight. It can be calculated using the equation: horizontal distance = (initial velocity * time * cosine of launch angle).


How do you determine the initial velocity in projectile motion?

To determine the initial velocity in projectile motion, you can use the equation v (x y) / t, where v is the initial velocity, x is the horizontal distance traveled, y is the vertical distance traveled, and t is the time taken.


What is the horizontal displacement of a projectile?

it depends on the gravitational force of attraction of earth and air resistance. if we are neglecting air resistance, the max.horizontal distance is according to this formulae, V0/2 * sin (2theta) where V0 is the initial velocity theta is the angle with x axis and the projection.


If Chris Bromham took off on his Yamaha and jumped a horizontal distance of 74.0 m across a row of cars and assuming that he started and landed at the same level and was airborne for 1.3 s, what was his initial (angled) velocity as he left the ground?

To find Chris Bromham's initial velocity when he left the ground, you can use the horizontal distance he traveled, the time he was in the air, and the acceleration due to gravity. The equation to use is: horizontal distance = horizontal velocity * time in the air. By rearranging the equation to solve for the horizontal velocity, you can find Chris Bromham's initial velocity when he left the ground.

Related Questions

What is the horizontal distance traveled by a projectile?

The horizontal distance traveled by a projectile is determined by the initial velocity of the projectile, the angle at which it was launched, and the time of flight. It can be calculated using the equation: horizontal distance = (initial velocity * time * cosine of launch angle).


What would happen if the initial horizontal velocity was increased?

Increasing the initial horizontal velocity of an object would cause it to cover more horizontal distance in the same amount of time, leading to a longer horizontal range. The object would maintain the same vertical acceleration due to gravity, so it would still follow a parabolic trajectory but reach a farther horizontal distance before hitting the ground.


How do you determine the initial velocity in projectile motion?

To determine the initial velocity in projectile motion, you can use the equation v (x y) / t, where v is the initial velocity, x is the horizontal distance traveled, y is the vertical distance traveled, and t is the time taken.


What is the horizontal displacement of a projectile?

it depends on the gravitational force of attraction of earth and air resistance. if we are neglecting air resistance, the max.horizontal distance is according to this formulae, V0/2 * sin (2theta) where V0 is the initial velocity theta is the angle with x axis and the projection.


If Chris Bromham took off on his Yamaha and jumped a horizontal distance of 74.0 m across a row of cars and assuming that he started and landed at the same level and was airborne for 1.3 s, what was his initial (angled) velocity as he left the ground?

To find Chris Bromham's initial velocity when he left the ground, you can use the horizontal distance he traveled, the time he was in the air, and the acceleration due to gravity. The equation to use is: horizontal distance = horizontal velocity * time in the air. By rearranging the equation to solve for the horizontal velocity, you can find Chris Bromham's initial velocity when he left the ground.


What do the horizontal motions of a projectile have in common?

The horizontal motions of a projectile are independent of its vertical motion. This means that the horizontal velocity remains constant and unaffected by gravity. Additionally, the horizontal distance traveled by a projectile is determined by the initial horizontal velocity and the time of flight.


In projectile motion What Angle would horizontal and vertical distance be equal?

Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.


What is the horizontal component of the initial velocity of the ball?

The horizontal component of the initial velocity of the ball is the velocity in the horizontal direction at the moment the ball is launched. It represents the speed and direction at which the ball is moving side-to-side.


What do you need to know to be able to determine how far a projectile travels horizontally?

To determine how far a projectile travels horizontally, you need to know the initial velocity of the projectile, the angle at which it was launched, and the acceleration due to gravity. Using these values, you can calculate the time of flight and then multiply it by the horizontal component of the initial velocity to find the horizontal distance traveled.


What is the horizontal range of a projectile initial velocity is doubled?

If "range" means that the shooter and the target are on the same level: quadrupled (if airesistance can be neglected). It takes twice the time until gravity "eats up" vertical velocity and during that time the projectile moves with double horisontal velocity. But if you shoot horisontally from a cliff at double velocity the flighttime will be the same and the range only doubled.


How do you find vertical and horizontal components when given the initial velocity?

If the initial velocity is v, at an angle x to the horizontal, then the vertical component is v*sin(x) and the horizontal component is v*cos(x).


A shell is fired from the ground with an initial velocity of 1600m s at an angle of 64 to the horizontal What is the shells horizontal range?

Using the projectile motion equations and given the initial velocity and angle, we can calculate the time the shell is in the air. Then, we can find the horizontal range by multiplying the time of flight by the horizontal component of the initial velocity. The horizontal range in this case is about 1056 meters.