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If Chris Bromham took off on his Yamaha and jumped a horizontal distance of 74.0 m across a row of cars and assuming that he started and landed at the same level and was airborne for 1.3 s, what was his initial (angled) velocity as he left the ground?
Lucas
I really need help. If someone can explain this to me, it'll be great!
Lucas
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In projectile motion What Angle would horizontal and vertical distance be equal?
Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.
How fast is an object moving at the instant it hits the top of its trajectory?
Assuming that there is no velocity in the horizontal direction, then the velocity at that instant is zero.
Does horizontal velocity effect the rate of vertical velocity?
No, horizontal velocity and vertical velocity are independent and have no effect on each other.
What do you need to know to be able to determine how far a projectile travels horizontally?
The horizontal velocity of the projectile (and the air resistance if known) will determine the horizontal distance traveled and the time required.
What is the value of constant horizontal velocity?
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
What is the formula for horizontal velocity?
Distance/Time d -- t
In a distance vs time graph if the line is perfectly horizontal what does that mean about the velocity of the object?
horizontal
In projectile motion What Angle would horizontal and vertical distance be equal?
Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.
How fast is an object moving at the instant it hits the top of its trajectory?
Assuming that there is no velocity in the horizontal direction, then the velocity at that instant is zero.
What does a horizontal line on a distance-time graph indicate?
It means there is no velocity - it is at rest and nothing is moving. The slope of the line is velocity - a horizontal line is zero slope = zero velocity
Explain how distance time and velocity are related to each other?
They are related through the formula distance = time x velocity (assuming constant velocity).
If you keep the velocity of projection constant and change the angle of projection from 75 to 45 what will happen to the horizontal distance the projectile travels?
The horizontal distance will be doubled.
How do you know there is no motion on a distance time-graph?
distance = velocity x time so on the graph velocity is slope. If slope is zero (horizontal line) there is no motion
How does the angle of release affect the motion of a projectile both vertical and horizontal?
Smaller angles will result in a larger horizontal velocity and smaller vertical velocity. The times of flight will also be shorter since it's closer to the ground. Larger angles have a larger vertical velocity and smaller horizontal velocity. Time of flight will be much longer since it is higher above the ground. As for distance, 45 degrees will result in the greatest distance and for every distance before the furthest one there is an angle above 45 degrees and an angle below 45 degrees that will result in that distance.
Does horizontal velocity effect the rate of vertical velocity?
No, horizontal velocity and vertical velocity are independent and have no effect on each other.
What kind of information is indicated by the graph of a landing site distance versus projectiles mass if the slope of the curve is zero?
Force = mass * acceleration Mass is only involved during the acceleration in the gun barrel , and is involved (with the explosive force) in translating to muzzle velocity. The horizontal distance travelled depends on the muzzle velocity and the incline of the barrel to horizontal. The curve will be parabolic even when the launch angle is 0 in which case the path will be negative (essentially going underground) 1. split launch velocity into horizontal and vertical vectors 2. using vertical velocity vector (initial velocity u), calculate (total) time to rise and fall back to ground using newtons equations. 3. multiply time by horizontal velocity vector to calculate horizontal distance travelled to landing site.
Calculate distance from a velocity time graph?
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
