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No. The combined thickness of the inner and outer core is about 3500 to 3520 kilometers, out of the Earth's total radius of about 6370 kilometers. This means that the combination of inner solid core and liquid outer core has about 16% of the Earth's volume. *The reference to "1% of the Earth's volume" may refer to the Earth's crust, which has about "1% of the Earth's total mass."
The core consists of an inner solid core with a radius of 760 miles, and an outer liquid core with a total diameter of 1400 miles. Applying the 4/3pi(r3) volume formula to these values we get: 1.8 billion cubic miles for the solid core and 11.7 billion cubic miles for the total outer and inner core volume. This compares to a total volume for the earth of 32.5 billion cubic miles.
Remembering that there is an inner core inside the outer core - the radius of the outer core/mantle boundary is about 3,400 km. (the diameter is twice the radius).
There is a rather large asteroid belt between Mars (the last inner planet) and Jupiter (the closest outer planet.) Mostly, however, the terminology refers to the vast difference in orbit radius between the inner and outer planets.
With a radius of 3396km, the planet Mars is about the same size as the inner and outer core of the earth (which is around 3490km radius in total).
pi(r2)of inner minus pi(r2) of outer. multiply height= volume or you could drop it in a beaker and see how much water was displaced
Outer volume = pi*142*40 cm3 Inner volume = pi*122*40 cm3 Volume of steel = Outer volume - Inner volume = pi*(142 - 122)*40 cm3 = pi*52*40 = 6535 cm3 approx.
4/3 * pi * (125 - 27)Improved answer with the same result:If the outer circumference is 10 times pi cm then its outer radius is 5 cm and its inner radius is 3 cm.outer volume - inner volume = volume of the sphere's shell(4/3*pi*53) - (4/3*pi*33) = 410.5014401 or 410.5 cubic cm to 1 decimal place
The inner circle is x2 + y2 = 4. The radius of the inner circle is the square root of 4, which is 2. To find the radius of the outer circle, multiply 2 times 4. The radius of the outer circle is 8. Square 8 (82 or 8 x 8) to find the number to put into the equation of the outer circle. This is 64. The equation for the outer circle is x2 + y2 = 64.
Surface area of a sphere = 4*pi*radius2 For a spherical shell, surface area = surface area of outer sphere - surface area of inner sphere = 4*pi*(outer radius)2 - 4*pi*(inner radius)2 = 4*pi*[ (outer radius)2 - (inner radius)2 ]
==================================Answer #2:I believe you want the volume of the shell ... the material between theinside and outside diameters ... whereas the first answer, above, gave youthe volume of the hole in the middle of everything. Here's my take on it:-- Volume of a sphere is 4/3 pi R3-- Volume enclosed by the outer radius is 4/3 pi (2)3-- Volume enclosed by the inner radius is 4/3 pi (1)3-- Volume of the material between them is4/3 pi (23 - 13) = 4/3 pi x 7 =28/3 pi = 29.32 m3. (rounded)The volume of a spherical shell is equal to the difference between the volume of a sphere with a radius of 2 m and a volume of a sphere with a radius of 1 meter:V= 29,321531433504736892318004910609 м3
x^2+y^2=36
No. The combined thickness of the inner and outer core is about 3500 to 3520 kilometers, out of the Earth's total radius of about 6370 kilometers. This means that the combination of inner solid core and liquid outer core has about 16% of the Earth's volume. *The reference to "1% of the Earth's volume" may refer to the Earth's crust, which has about "1% of the Earth's total mass."
It is not possible to find the volume from the two radii. That will only give the surface area of the disk that it forms. To find the volume yYou also need the thickness of .
A sphere, of radius a = 11.4 cm and charge q = 5.00 × 10 − 6 C uniformly distributed throughout its volume, is concentric with a spherical conducting shell of inner radius b = 26.2 cm and outer radius c = 28.2 cm . This shell has a net charge of -q. visit our page : grandarchinex.co.in
You must use the relationship between the inner radius and the outer radius. The relationship could very well be different every time you run into a problem like this, and I can't answer the question this time because you haven't described any relationship between them.
The core consists of an inner solid core with a radius of 760 miles, and an outer liquid core with a total diameter of 1400 miles. Applying the 4/3pi(r3) volume formula to these values we get: 1.8 billion cubic miles for the solid core and 11.7 billion cubic miles for the total outer and inner core volume. This compares to a total volume for the earth of 32.5 billion cubic miles.