6.8 X 10^-5 M/s
The instantaneous rate of a reaction at t=800 seconds can be determined by calculating the slope of the tangent line to the concentration-time curve at that specific point in time. This slope represents the rate of the reaction at that moment, giving you the instantaneous rate at t=800 seconds.
The rate law for a chemical reaction expresses how the rate of the reaction depends on the concentration of reactants. By plugging in the instantaneous concentrations of the reactants into the rate law equation, we can calculate the instantaneous reaction rate at a specific moment in time.
To solve for the half-life of a first-order reaction, you can use the equation t1/2 = 0.693/k, where k is the rate constant. Plugging in the given rate constant of 0.0000739, you get t1/2 = 0.693 / 0.0000739 = 9376.63 seconds. Therefore, the half-life of this reaction is approximately 9376.63 seconds.
The rate constant is not indicative of the order of the reaction. To determine the order of the reaction, experimental data (such as concentration vs. rate data) is needed. The order of the reaction can be found by examining how changes in reactant concentrations affect the rate of the reaction.
The product and reactants reach a final, unchanging level.
The effect of concentration of reactants on rate of reaction depends on the ORDER of the reaction. For many reactions, as the concentration of reactants increases, the rate of reaction increases. There are exceptions however, for example a zero order reaction where the rate of reaction does not change with a change in the concentration of a reactant.
6.8 X 10^-5 M/s
The rate law for a chemical reaction expresses how the rate of the reaction depends on the concentration of reactants. By plugging in the instantaneous concentrations of the reactants into the rate law equation, we can calculate the instantaneous reaction rate at a specific moment in time.
When an equation is balanced, the rate of the forward reaction equals the rate of the reverse reaction.
Chemical equilibrium results if the rates of the forward and reverse reactions are equal, leading to a balanced state where the concentrations of reactants and products remain constant over time. This occurs when the system reaches a point where the rate of the forward reaction is equal to the rate of the reverse reaction, allowing for a dynamic but stable state.
It is irrelevant what the independent variable is, whenever you work out rate of reaction you also divide 1 by the time in seconds. For example if it took 100 seconds your rate would be 0.01s-1.
The product and reactants reach a final, unchanging level.
yes
The two kinds of equilibrium are static equilibrium, where an object is at rest with no linear or angular acceleration, and dynamic equilibrium, where an object is moving at a constant velocity with no linear or angular acceleration.
The rate of change in position at a given point in time is instantaneous speed, instantaneous velocity.
To solve for the half-life of a first-order reaction, you can use the equation t1/2 = 0.693/k, where k is the rate constant. Plugging in the given rate constant of 0.0000739, you get t1/2 = 0.693 / 0.0000739 = 9376.63 seconds. Therefore, the half-life of this reaction is approximately 9376.63 seconds.
It will decrease by half.
The rate of change in position at a given point in time is instantaneous speed, instantaneous velocity.