6.8 X 10^-5 M/s
The rate law for a chemical reaction expresses how the rate of the reaction depends on the concentration of reactants. By plugging in the instantaneous concentrations of the reactants into the rate law equation, we can calculate the instantaneous reaction rate at a specific moment in time.
Since the reaction is first-order, the half-life is constant and equals ln(2)/k, and the units of k are s-1. In this case, the half-life is ln(2)/(.0000739 s-1) = 9379.529 seconds.
The rate constant is not indicative of the order of the reaction. To determine the order of the reaction, experimental data (such as concentration vs. rate data) is needed. The order of the reaction can be found by examining how changes in reactant concentrations affect the rate of the reaction.
In chemistry, the symbol s-1 represents the unit of inverse seconds, which is used to measure the rate of a reaction. It indicates how quickly a chemical reaction is occurring, with a higher value of s-1 indicating a faster reaction rate.
The product and reactants reach a final, unchanging level.
6.8 X 10^-5 M/s
The rate law for a chemical reaction expresses how the rate of the reaction depends on the concentration of reactants. By plugging in the instantaneous concentrations of the reactants into the rate law equation, we can calculate the instantaneous reaction rate at a specific moment in time.
Since the reaction is first-order, the half-life is constant and equals ln(2)/k, and the units of k are s-1. In this case, the half-life is ln(2)/(.0000739 s-1) = 9379.529 seconds.
yes
The rate of change in position at a given point in time is instantaneous speed, instantaneous velocity.
The rate of change in position at a given point in time is instantaneous speed, instantaneous velocity.
The rate of change in position at a given point in time is instantaneous speed, instantaneous velocity.
It will decrease by half.
It is irrelevant what the independent variable is, whenever you work out rate of reaction you also divide 1 by the time in seconds. For example if it took 100 seconds your rate would be 0.01s-1.
Finding the rate of change - in particular, the instantaneous rate of change.
1) Find time = 10 s on the curve. 2) Draw a line tangent to the point time = 10 s on the curve. 3) Use two points on the tangent line to find the slope of the line. 4) The slope of the line is the instantaneous rate in M/s.
At equilibrium, the net rate of the reaction is zero, meaning that the rate of the forward reaction equals the rate of the reverse reaction. This balance results in no net change in the concentrations of the reactants and products over time. Although individual molecular events continue to occur, the overall concentrations remain constant.