6.8 X 10^-5 M/s
The Instantaneous rate, or the rate of decomposition at a specific time, can be determined by finding the slope of a straight line tangent to the curver at that instant.
The product and reactants reach a final, unchanging level.
Since the reaction is first-order, the half-life is constant and equals ln(2)/k, and the units of k are s-1. In this case, the half-life is ln(2)/(.0000739 s-1) = 9379.529 seconds.
The time it takes for a reaction to occur is a function of the reaction rate constant and the amount of reactants. However, how long it takes for a reaction of occur completely depends on the type of reaction it is -- what the order of the reaction is. A first or second order reaction reaction will occur much faster earlier on, but slows down significantly once the reactants are depleted. The rate of a zero order reaction is constants regardless of the concentration of the reactants.
The overall reaction order for k[A]^2[B][C] would be 4 Because [A] has a rate order of 2 [B] has a rate order of 1 [C] has a rate order of 1 And when you add them together... 2 + 1 + 1 You obtain four
6.8 X 10^-5 M/s
The Instantaneous rate, or the rate of decomposition at a specific time, can be determined by finding the slope of a straight line tangent to the curver at that instant.
When an equation is balanced, the rate of the forward reaction equals the rate of the reverse reaction.
forward reaction rate equals reverse reaction rate
It is irrelevant what the independent variable is, whenever you work out rate of reaction you also divide 1 by the time in seconds. For example if it took 100 seconds your rate would be 0.01s-1.
The product and reactants reach a final, unchanging level.
yes
The two kinds of equilibrium are the folowing:Physical, which is an open system, and the rate of substances in, equals the rate of substances out.The other equilibrium is chemical equilibrium, which is a closed system, and the rate of the forward reaction equals the rate of the reverse reaction.
The rate of change in position at a given point in time is instantaneous speed, instantaneous velocity.
Since the reaction is first-order, the half-life is constant and equals ln(2)/k, and the units of k are s-1. In this case, the half-life is ln(2)/(.0000739 s-1) = 9379.529 seconds.
It will decrease by half.
The rate of change in position at a given point in time is instantaneous speed, instantaneous velocity.