6.8 X 10^-5 M/s
The instantaneous rate of a reaction at t=800 seconds can be determined by calculating the slope of the tangent line to the concentration-time curve at that specific point in time. This slope represents the rate of the reaction at that moment, giving you the instantaneous rate at t=800 seconds.
The rate law for a chemical reaction expresses how the rate of the reaction depends on the concentration of reactants. By plugging in the instantaneous concentrations of the reactants into the rate law equation, we can calculate the instantaneous reaction rate at a specific moment in time.
Since the reaction is first-order, the half-life is constant and equals ln(2)/k, and the units of k are s-1. In this case, the half-life is ln(2)/(.0000739 s-1) = 9379.529 seconds.
yes
The rate of change in position at a given point in time is instantaneous speed, instantaneous velocity.
The rate of change in position at a given point in time is instantaneous speed, instantaneous velocity.
The rate of change in position at a given point in time is instantaneous speed, instantaneous velocity.
It will decrease by half.
It is irrelevant what the independent variable is, whenever you work out rate of reaction you also divide 1 by the time in seconds. For example if it took 100 seconds your rate would be 0.01s-1.
Finding the rate of change - in particular, the instantaneous rate of change.
1) Find time = 10 s on the curve. 2) Draw a line tangent to the point time = 10 s on the curve. 3) Use two points on the tangent line to find the slope of the line. 4) The slope of the line is the instantaneous rate in M/s.
At equilibrium, the net rate of the reaction is zero, meaning that the rate of the forward reaction equals the rate of the reverse reaction. This balance results in no net change in the concentrations of the reactants and products over time. Although individual molecular events continue to occur, the overall concentrations remain constant.