Top Answer

Assume the expression is:

∫ sin(x)x²e^x dx

Then:

Take the integral: integral e^x x^2 sin(x) dx For the integrand e^x x^2 sin(x), integrate by parts, integral f dg = f g- integral g df, where f = x^2, dg = e^x sin(x) dx, df = 2 x dx, g = 1/2 e^x (sin(x)-cos(x)): = 1/2 e^x x^2 sin(x)-1/2 (e^x x^2 cos(x))- integral e^x x (sin(x)-cos(x)) dx Expanding the integrand e^x x (sin(x)-cos(x)) gives e^x x sin(x)-e^x x cos(x): = 1/2 e^x x^2 sin(x)-1/2 (e^x x^2 cos(x))- integral (e^x x sin(x)-e^x x cos(x)) dx Integrate the sum term by term and factor out constants: = 1/2 e^x x^2 sin(x)-1/2 (e^x x^2 cos(x))- integral e^x x sin(x) dx+ integral e^x x cos(x) dx For the integrand e^x x sin(x), integrate by parts, integral f dg = f g- integral g df, where f = x, dg = e^x sin(x) dx, df = dx, g = 1/2 e^x (sin(x)-cos(x)): = 1/2 e^x x^2 sin(x)-1/2 e^x x^2 cos(x)-1/2 e^x x sin(x)+1/2 e^x x cos(x)+ integral e^x x cos(x) dx+1/2 integral e^x (sin(x)-cos(x)) dx Expanding the integrand e^x (sin(x)-cos(x)) gives e^x sin(x)-e^x cos(x): = 1/2 e^x x^2 sin(x)-1/2 e^x x^2 cos(x)-1/2 e^x x sin(x)+1/2 e^x x cos(x)+ integral e^x x cos(x) dx+1/2 integral (e^x sin(x)-e^x cos(x)) dx Integrate the sum term by term and factor out constants: = 1/2 e^x x^2 sin(x)-1/2 e^x x^2 cos(x)-1/2 e^x x sin(x)+1/2 e^x x cos(x)+1/2 integral e^x sin(x) dx-1/2 integral e^x cos(x) dx+ integral e^x x cos(x) dx For the integrand e^x cos(x), use the formula integral exp(alpha x) cos(beta x) dx = (exp(alpha x) (alpha cos(beta x)+beta sin(beta x)))/(alpha^2+beta^2): = 1/2 e^x x^2 sin(x)-1/2 e^x x^2 cos(x)-1/4 e^x sin(x)-1/2 e^x x sin(x)-1/4 (e^x cos(x))+1/2 e^x x cos(x)+1/2 integral e^x sin(x) dx+ integral e^x x cos(x) dx For the integrand e^x sin(x), use the formula integral exp(alpha x) sin(beta x) dx = (exp(alpha x) (alpha sin(beta x)-beta cos(beta x)))/(alpha^2+beta^2): = 1/2 e^x x^2 sin(x)-1/2 e^x x^2 cos(x)-1/2 e^x x sin(x)-1/2 (e^x cos(x))+1/2 e^x x cos(x)+ integral e^x x cos(x) dx For the integrand e^x x cos(x), integrate by parts, integral f dg = f g- integral g df, where f = x, dg = e^x cos(x) dx, df = dx, g = 1/2 e^x (sin(x)+cos(x)): = 1/2 e^x x^2 sin(x)-1/2 e^x x^2 cos(x)+e^x x cos(x)-1/2 e^x cos(x)-1/2 integral e^x (sin(x)+cos(x)) dx Expanding the integrand e^x (sin(x)+cos(x)) gives e^x sin(x)+e^x cos(x): = 1/2 e^x x^2 sin(x)-1/2 e^x x^2 cos(x)+e^x x cos(x)-1/2 e^x cos(x)-1/2 integral (e^x sin(x)+e^x cos(x)) dx Integrate the sum term by term: = 1/2 e^x x^2 sin(x)-1/2 e^x x^2 cos(x)+e^x x cos(x)-1/2 e^x cos(x)-1/2 integral e^x sin(x) dx-1/2 integral e^x cos(x) dx For the integrand e^x cos(x), use the formula integral exp(alpha x) cos(beta x) dx = (exp(alpha x) (alpha cos(beta x)+beta sin(beta x)))/(alpha^2+beta^2): = 1/2 e^x x^2 sin(x)-1/2 e^x x^2 cos(x)-1/4 e^x sin(x)+e^x x cos(x)+-3/4 e^x cos(x)-1/2 integral e^x sin(x) dx For the integrand e^x sin(x), use the formula integral exp(alpha x) sin(beta x) dx = (exp(alpha x) (alpha sin(beta x)-beta cos(beta x)))/(alpha^2+beta^2): = 1/2 e^x x^2 sin(x)-1/2 e^x x^2 cos(x)-1/2 e^x sin(x)+e^x x cos(x)-1/2 e^x cos(x)+constant Which is equal to: Answer: | | = 1/2 e^x ((x^2-1) sin(x)-(x-1)^2 cos(x))+constant

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0By using the chain rule. Since the derivative of exp(x) is exp(x), the derivative of exp(exp(exp(x))) is exp(exp(exp(x))) times the derivative of what is inside the parentheses, i.e., exp(exp(exp(x))) times derivate of exp(exp(x)). Continue using the chain rule once more, for this expression.

No. you just get the exp. points! :^)

9.89 exp-1 (9.89 times 10 to the -1 power)

Nothing you just get EXP from them that's it.

Give him an EXP SHARE, and go trough the pokémon league (a couple of times) Use an other pokémon, not magikarp, but keep him in your team. He will get EXP without battling.

I suggest you give poliwrath the exp share and go through the elite 4 a bunch of times

Yes they do(1.5 times the exp a regularly caught Pokemon will get), but if they are a higher level of your badge alows them to listen to you, they will use random moves,ignore orders, don't listen to you, and fall asleep in the middle of battles.

No, it doesn't help you 'literally' but it is convenient because chemistry uses a lot of calculation: generally 'solving equations' most commonly + - : x log less commonly exp 'square root' integral/differential etc.

Do bounty hunting lot of times until u come to an enemy which gives ya 600 gold(maximum)

You can give it to a Pokemon you want to lvl up fasterit give two times the experience point

Exp share at elite four a couple times that's how i got a lv. 100 tepig

Yes one is 1 loop catch and exp times

to train your Pokemon quick you need to get a exp share by getting a red scale then trading it with mr.pokemons exp share.then give it to your Pokemon and then beat all the gym leaders/red and then beat the elite four a couple of times simple

The definite integral of the function f=x*exp(k*x) is (1/k)*(x-(1/k))*exp(k*x). So you have the answer to your questions by setting k equal to 1 then 2. I derived my formula by using integration by parts, setting u=x and dv=exp(k*x)dx.

First of all, you have to have a scientific calculator, one that supports scientific notation. (As far as I know, all scientific calculators do.) The scientific calculator should have a special key labelled something like EXP. To input (for example) 2.3 million, you would type 2.3 EXP 6 (where EXP is short for "times 10 to the power...").

Negative square roots are just the opposite of positive square roots. Since square roots (of positive numbers) are real, the negative square roots are also real.Square roots of negative numbers are not real.Note that -1 = exp(Pi*i), so (-1)^(1/2) = exp((1/2)*Pi*i) = i.Note that exp(i*x) = cos(x) + i*sin(x), for instance by taking derivatives:(d/dx)(exp(i*x)) = i*exp(i*x), and(d/dx)^2(exp(i*x)) =(-1)*exp(i*x).This means that the second derivative of exp(i*x) equals -exp(i*x).The same property holds for cos(x) + i*sin(x):(d/dx)(cos(x) + i*sin(x)) = -sin(x) + i*cos(x)(d/dx)^2(cos(x) + i*sin(x)) = -cos(x) - i*sin(x) = -(cos(x) + i*sin(x)))Hence cos(x) + i*sin(x)) = C + Dx + exp(i*x), for some C and D.Comparing the values on both sides for x = 0, we find:1 = C+1, so C = 0 and for the first derivative:i = D + i, so D = 0.So cos(x) + i*sin(x)) = exp(i*x) for all x.by comparing x=0 for both functions and their first derivative. Since they coincide,

The hypoexponential distribution is two or more exponential distribution convolved together, so:hypo[x] = integral of A*exp(-A*x)*B*exp(-B*(t-x)) from 0 to t.If you have more stages you do more convolutions.

its an non integrable functionThe indefinite integral of exp(x^2) dx is1/2 * sqrt(pi) * erfi(x) + Kwhere erfi(x) is the imaginary error function, defined with regard to the error function aserfi(x) = - i erf(ix)see http://mathworld.wolfram.com/Erfi.htmlAlso, try wolframalpha.com, enterexp(x^2) in the search box orint(exp(x^2),x)to see some plots and other info.Answere^(x^2) is an example of a function expressible using standard functions (+, *, exp, log, atan, etc) whose integral can not be expressed in this way. In such cases we invent a name for the function defined by the interval, but it's just a name and doesn't shed any light on the function. In short, there is no intellectually satisfying answer to this question.

It is most certainly NOT impossible like people would suggest although it isn't logical because every time you go to a new area your exp goes down to 0% and your exp goes down to 0% at random times.

A square pyramid's base is a square. You can tell by the name (for exp. a triangular pyramid's base is a triangle.) Good luck with whatever you need it for :)

The amount of exp you lose depends on if your oppent is a higher or lower rank than you. If he is higher, you will not lose much exp, if his lvl is lower, you will lose more exp. Note: You only lose/earn exp on LADDER MATCHES.

exp ? exp : exp

The following Quests give you thieving XP:-Mourning's End part 1 - 25,000 expRocking out - 25,000 expThe Chosen Commander - 20,000 expThe Feud - 15,000 expCurse of Arrav- 14,000 expContact - 7,000 expDarkness of Hallovale- 6,000 expDealing with Scabaras- level 7,000 expGrim Tales - 6,000 expThe path of Glouphrie - 5,000 expIcthlarin's Little Helper- 4,500 expRat Catcher - 4,500 expSlug Menace- 3,500 expFight Arena- 3,375 expLand of Goblins - 3,000 expFermanik Trials- 2,813 expFairy tale part2: Cure a Queen - 2,500 expDeath to Dorgeshunn - 2,000 expHunt for Red Raktuber- 2,000 expHazeel Cult- 1,500 expBiohazard - 1,500 expTribal Totem- 1,250 expThe Golem- 1,000 expCreature of Fenkenstrain- 1,000 expSpirits of the Elid - 1,000 expHand in the Sand - 1,000 expPerils of Ice Mountain - 500 expTower of Life - 500 exp

you can cheat by playing 2 balls lots of times but get someone to let u win so many times its the best way to get exp trust me, don't use cheat engines because they hack ur PC and get a virus into it. kitkat tried the cheat engine but thankfully in her frineds PC lol he got a virus in there but it recovered by deleting the program/software anyways hope i asnwerd ur queston

you go up exp by winning and lose exp by quitting

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