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(assuming no air resistance)

potential energy translated to kinetic energy.

you need some numbers in:

potential energy = m*g*h = 15 000 j

say m = 100 kg

say g = 10 m/s^2 (approximation)

then h = 15 000 / (100*10) = 15 metres

so

100 kg after falling 15 metres will have kinetic energy = 15 000 joules

KE = 0.5 * m * v^2

so velocity) at base of tower :

v =square root (15 000 / (0.5 * 100))

v = 17.32 metres / second

so , potential energy lost = kinetic energy gained.

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Q: What is the kinetic energy of a person on top of a tower e equals with a potential energy of 15000 joules?
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