The smallest possible perimeter is 20-ft, but there is no largest possible perimeter.
You can make it as large as you want, with no limit.
5-ft x 5-ft . . . . area = 25 ft2 . . . perimeter = 20 ft
2.5-ft x 10-ft . . area = 25 ft2 . . . perimeter = 25 ft
1-ft x 25-ft . . . area = 25 ft2 . . . Perimeter = 52 ft
6-in x 50-ft . . . area = 25 ft2 . . . Perimeter = 101 ft
3-in x 100-ft . . area = 25 ft2 . . . perimeter = 2001/2 ft
1-in x 300-ft . . area = 25 ft2 . . . perimeter = 6001/6 ft
0.1-in x 3,000-ft . . area = 25 ft2 . . . perimeter = 6,0001/60 ft
Twice (length + width)
Add together the 4 sides
The answer is 28cm
The formula for finding the perimiter of a rectangle is add up all of its sides
to find the perimiter you just add up all the sides....Perimiter is the same for every figure.
Largest = 86, Smallest 26
The smallest is just over 40 units. At 40 units it is no longer a rectangle but a square. There is no largest perimeter.
11 x 12 rectangle has a larger perimeter = 46 units The 132 square unit area will give a square a perimeter of 45.9565 units
Perimeter = 33+33+3+3 = 72 m
4.5+4.5+1.5+1.5 = a perimeter of 12 meters
The smallest perimeter is 4*sqrt(24) = approx 19.6 cm There is no largest perimeter.
There is no such thing as a three sided rectangle. They have four sides. Length and width of a rectangle being THE SAME (having a 1:1 ratio) will provide the largest area possible. In other words, for a given perimeter, a square is the largest rectangle. If you mean a triangle (which has three sides), then all sides being equal will still yield the largest area.
be more specific area=base x height perimiter= add all sides together
The answer is 40 (cm?). 6 + 6 (both sides) +14+14= 40
The area is the inside. The perimiter is around. If its a rectangle, to find the area you multiply the lengths of two sides
it measures by perimiter it measures by perimiter
If the perimiter is 20 and one side is [[length]] then the other side is (10 - [[length]]). So the area is: [[length]] x (10 - [[length]]) square metres.
The perimeter of a rectangle is twice the length plus twice the width.20' x 2 = 40'100' - 40' = 60'60' / 2 = 30'
I would start with the largest possible rectangle. What's left should be a collection of triangles.
The outer boundary of a body or figure.
In order to know the perimeter of a rectangle, you need to know both its length and its width ... two numbers. One number isn't enough. If one side of a rectangle is 22 feet, then the perimeter of the rectangle can be any number greater than 44 feet. There are an infinite number of different possibilities.
L + W = P/2 = 42 ft. 1/7th of 42 is 6 so L = 36 and W = 6 making the area 216 sqft.
By definition, no rectangle is a square - they are two different figures. If you draw a true rectangle, it is not a square - it is a rectangle.
Not sure if this is what is required, but the area of the largest square that will fit in a 18 by 9 rectangle is 9 by 9.