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That depends on many factors. Best way is to measure the particular model of TV in question. Next best is to read the published dimensions in a catalog or other marketing material, though these are not always exactly correct. There may be protrusions for antenna, cables or space required around the set for mounting, cooling, operating controls or your hand while connecting. To get an approximation we need to answer these questions: * Widescreen or Standard aspect ratio? * ** Widescreen is in the ratio 16wide x 9high ** Standard is in the ratio 4wide x 3high * Does "54 tv" refer to a diagonal corner to corner measurement in inches? * How much area borders the screen? * ** What sides are the speakers on and how big are they? * What type of TV is it? determines depth or length. * ** Tube about 30" ** Projection about 24" ** Flat panel plasma or LCD about 4" So for a widescreen the screen dimension would be about * Your viewing area is 47.1 in(w) x 26.5 in(h) * Total viewing area is 1248.15 sq in. For a standard screen * Your viewing area is 43.2 in(w) x 32.4 in(h) * Total viewing area is 1399.68 sq in. Assuming a 54" widescreen LCD with speakers on the side, total outside dimensions would be approximately 57"w x 36"h x 4"l plus add 1.5"mounting depth if wall mounted.
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What is the length of the rectangle if the perimeter is 54 cm and it's length is twice it's width?
Let its width be x:- 2(2x+x) = 54 => 4x+2x = 54 => 6x = 54 => x = 9 Therefore: width = 9 cm and length = 18 cm
What is the length width and height of an 50 tv?
depends on brand and which TV of that brand
The length of a rectangle is 6 times the width The area is 54 square centimeters find the length and width of the rectangle?
6w * w =54w=3L= 6*3=18
What is the perimeter of a 12ft long and 15ft wide room?
2*(length + width) = 54 feet.
A contractor needs 54 square feet of brick to construct a rectangular walkway. The length of the walkway is 15 more than the width Write an equation that is the answer?
A contractor needs 54 square feet of brick to construct a rectangular walkway. The length of the walkway is 15 more than the width Write an equation that is the answer? Ans: I L = length and W = width, then L = W + 15; area = LW = 54, so (W+15)W = 54, i.e. WxW + 15W - 54 = 0; solving this gives W = 3, so L = 18.
If the length of a rectangle is 7 centimeters greater than the width. The perimeter is 54 centimeters. Find the length and the width.?
width:10,length;17 17*2+10*2=54
What is the length of the rectangle if the perimeter is 54 cm and it's length is twice it's width?
Let its width be x:- 2(2x+x) = 54 => 4x+2x = 54 => 6x = 54 => x = 9 Therefore: width = 9 cm and length = 18 cm
The width of a rectangle is one half its length the perimeter of the rectangle is 54 cm what are the width and length of the rectangle?
width=9 length=18
What would be the length and width of a tv screen with a diagonal of 22?
The length and width would be equal to 22^2 = length^2 + width^2 444 = length^2 + width^2 Assuming the screen is a square, then 444 = 2length^2 222 = length^2 root(222) = length = width
What is is the length of a yard with an area of 54 and a width of 8?
The length would be 6.5. Since you have the area divide that by the width.
The length of a rectangle is 7 centimeters greater than the width The perimeter is 54 centimeters Find the length and the width?
Length 17 cm. Width 10 cm.
What is the area of a rectangle with these measurements Length 54 inches by Width 36 inches?
1944 in. Length x Width = Area
What is the length of a rectangle if its width is 9inches and the perimeter is 54 inches?
Perimeter = 2*(Length + Width) 54 = 2*(L + 9) = 2L + 18 So 2L = 54 - 18 = 36 and therefore L = 18 inches.
What is the perimeter in feet of a rectangle whose length is twice its width and whose width is 9 feet?
If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.
What is the length width and height of an 50 tv?
depends on brand and which TV of that brand
Is television a 2D shape or 3D shape?
A television set is a 3D shape. The image (picture) on the television screen is a 2D shape. 3D is when it has length, width, and height. 2D is only length and width.
What is the length and width of a rectangle whose area is 54?
9 x 6
