The area is not sufficient information to determine the length and width.
First of all, there is no reason to suppose that the area is rectangular as opposed to circular or triangular or some other simple or complicated shape. Even if, on the basis that the question asks for length and width, you assume that it is a rectangle, there are infinitely many possible answers.
Consider a rectangle whole lenght, L is any number greater than or equal to sqrt(46) units, and let W = 46/L units be its width.
Then area = LxW = Lx46/W = 46 units.
But L is any one of infinitely many numbers, and so there are infinitely many solutions.
The surface area is 46 square feet.
perimeter = 14+14+9+9 = 46 meters area = 14*9 = 126 square meters
You can't tell. There are an infinite number of sets of length and width that havea diagonal of 46.The only thing we know for sure is that whatever they are, the square of the lengthand the square of the width add up to 2,116.
If those are the dimensions of the walkway, then the area is 2,300 square feet or 255.6 square yards. If those are the dimensions of the pool, then we can't calculate the area of the walkway until you tell us how wide you want it to be.
Perimeter = 2 x (length + width), area = Length x width. Perimeter is not directly related to area except in the cases of circles and squares. Consider a rectangle of 60 sq cm: the integer possibilities for length and width are numerous: 1 x 60, 2 x 30, 3 x 20, 4 x 15, 5 x 12 and 6 x 10. The respective perimeters are 122 cm, 100 cm, 46 cm, 38 cm, 34 cm and 32 cm. Note that the nearer the shape becomes to a square, the smaller the perimeter. (A square would have a perimeter of a whisker under 31 cm.)
In a rectangle, the area is calculated by multiplying length x width. If (for example) both length and width are in centimeters, the area will be in square centimeters.
The area of rectangle is : 7820.0
area on conversion is : area =46 X60=2760 ft 2
92 metres.
The surface area is 46 square feet.
The perimeter which is 2*(L+W) where L = length = 46 ft and W = width = 34 ft So 2*(46+34) ft = 2*80 ft = 160 ft
perimeter = 14+14+9+9 = 46 meters area = 14*9 = 126 square meters
46 centimeters
A rectangle which is 46 feet by 34 feet would have two sides of length 46 and two sides of length 34. Add these together to get the total length needed to enclose the area. (46+46+34+34)ft = 160ft
A rectangular prism with a length of 46km, a width of 32km and a height of 29km has a volume of 42,688km3
You can't tell. There are an infinite number of sets of length and width that havea diagonal of 46.The only thing we know for sure is that whatever they are, the square of the lengthand the square of the width add up to 2,116.
i don't know what length of rectangle is 7 cm longer than the width the perimeter of the rectangle is 46 cm .what is the length of the of the rectangle ?