perimeter of octagon is 128 cm= 8 * side
side of the octagon=128/8=16 cm
Perimeter = 2*(Length+Width) So 36 = 2*(L+4) 18 = L+4 or L = 14
The third side can be of any length in the interval (2, 128) units of length.
L = 2W 2W x W = 128 2W squared = 128 w squared = 64 W = 8 Width 8 ft, length 16 ft 8 x 16 = 128 QED
16
Let the width be x/2 and the length be x: (x/2)*x = 128 Multiply both sides by 2 and remove the brackets: x2 = 256 Square root both sides: x = 16 Therefore: length = 16 feet and width = 8 feet Check: 16*8 = 128 square feet
16 cm for each side
128 cm = 50.394 inches.
Perimeter of rectangle = 2 x ( L + W ) = 2 x 64 = 128 cm. or Perimeter of rectangle = 2L + 2W = 68 + 60 = 128 cm.
Let the length be 2x+7 and the width be x: 2(length+width) = perimeter 2(2x+7+x) = 128 4x+14+2x = 128 4x+2x = 128-14 6x = 114 x = 19 Therefore: length = 45m and width = 19m Check: 45+45+19+19 = 128m
It is: 128/4 = 32 which is a side of the square and so 32*pi is the circumference of the circle
Perimeter = 2*(Length+Width) So 36 = 2*(L+4) 18 = L+4 or L = 14
128
The square root of 128, approxiametaly 11.313
The third side can be of any length in the interval (2, 128) units of length.
128 cm
128 feet.
It is: 128/4 = 32 and 32*32 = 1024 square cm