area of triangle e= 1/2 X base Xheight
32 = 1/2 X base X 8
base =32/4 =8 inches
18 square inches is probably the area of the triangle, not the length of the base. The length of the base would be measured in inches (a unit of length), not square inches (a unit of area). So area = 1 / 2 * base * height = 18 square inches (given) height = 4 * base (given) 1 / 2 * base * 4 * base = 18 square inches 2 * base * base = 18 square inches base * base = 9 square inches base = 3 inches height = 4 * base = 4 * 3 inches = 12 inches Checking our work: height is 4 times the base (12 = 4 * 3) area is 18 (1/2 * 12 * 3).
I suppose by "length of a triangles altitude" you mean height. The height of the triangle in question cannot be determined from the information given. In order to determine the height of the triangle, two dimensions must be known.
the formula for the area of a triangle is; a=1/2 base times height. so for example: a triangle may have a base length of 6 inches and a height of 3 inches. a=1/2 6(3) the answer would be: 9 inches.
The hypotenuse of a right triangle with a base of 24 inches and height of 10 inches is: 26 inches.
-- Measure the length of the base, in inches. -- Measure the height of the triangle, in inches. -- Multiply the two numbers and take 1/2 of the product. 1/2 of the product is the area of the triangle, in square inches.
48in2. To find the area of any triangle - you divide the length of the base by 2, then multiply that figure by the height.
18 square inches is probably the area of the triangle, not the length of the base. The length of the base would be measured in inches (a unit of length), not square inches (a unit of area). So area = 1 / 2 * base * height = 18 square inches (given) height = 4 * base (given) 1 / 2 * base * 4 * base = 18 square inches 2 * base * base = 18 square inches base * base = 9 square inches base = 3 inches height = 4 * base = 4 * 3 inches = 12 inches Checking our work: height is 4 times the base (12 = 4 * 3) area is 18 (1/2 * 12 * 3).
31.5 sq. in.
The first is clearly not a suitable triangle.
16.97056275 or about 17 inches
The length of a triangle with a height of 12 inches and an area of 18 square inches is 3 inches, since area is 1/2 * base * height. Therefore, 2 * area divided by height = 2 * 18 /12 = 3
Area Rectangle = 12 * 8 = 96 sq. in.Area Triangle = 1/2 base * height -> 96 = 16 * height -> 96 / 16 = height = 6 in.
Perimeter: 5+10+length of its 3rd side
I suppose by "length of a triangles altitude" you mean height. The height of the triangle in question cannot be determined from the information given. In order to determine the height of the triangle, two dimensions must be known.
18 square inches
the formula for the area of a triangle is; a=1/2 base times height. so for example: a triangle may have a base length of 6 inches and a height of 3 inches. a=1/2 6(3) the answer would be: 9 inches.
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?